Java android中使用截取的嵌套JSON对象解析

我需要您帮助解析嵌套的JSON对象

附加JSON数据：

{
  "31": {
    "basic": {
      "node_id": "31",
      "title": "test",
      "alias": "test",
      "description": "test",
      "site_id": "151336557",
      "node_type": "7",
      "privacy": "7",
      "deleted": "0",
      "status": "1",
      "created_date": "1379169518",
      "updated_date": "1379169518",
      "created_by": "140513626519686828",
      "updated_by": null,
      "readable_date": "14th Sep, 2013"
    },
    "meta": {
      "forum_id": "61"
    },
    "comments": {
      "count": 1
    },
    "likes": {
      "count": 0
    },
    "tags": [],
    "node_id": "31"
  },
  "32": {
    "basic": {
      "node_id": "32",
      "title": "testing discussion",
      "alias": "testing-discussion",
      "description": "testing",
      "site_id": "151336557",
      "node_type": "7",
      "privacy": "7",
      "deleted": "0",
      "status": "1",
      "created_date": "1379493816",
      "updated_date": "1379493816",
      "created_by": "140513795022034166",
      "updated_by": null,
      "readable_date": "18th Sep, 2013"
    },
    "meta": {
      "forum_id": "65"
    },
    "comments": {
      "count": 1
    },
    "likes": {
      "count": 0
    },
    "tags": [],
    "node_id": "32"
  }
}

附加Java代码：

private void makeJsonObjectRequest() {
     showpDialog();

     JsonObjectRequest jsonObjReq = new JsonObjectRequest(Method.GET,            urlJsonObj, null, new Response.Listener<JSONObject>() {

         @Override
         public void onResponse(JSONObject response) {
             Log.d(TAG, response.toString());

             JSONObject phone = response.getJSONObject("31").getJSONObject("basic");
             String name = phone.getString("title");
             String email = phone.getString("description");
             JSONObject comments = response.getJSONObject("31").getJSONObject("comments");
             String home = comments.getString("count");
             JSONObject like = response.getJSONObject("31").getJSONObject("likes");
             String mobile = like.getString("count");

             jsonResponse = "";
             jsonResponse += "Name: " + name + "\n\n";
             jsonResponse += "Email: " + email + "\n\n";
             jsonResponse += "Home: " + home + "\n\n";
             jsonResponse += "Mobile: " + mobile + "\n\n\n";

             txtResponse.setText(jsonResponse);

private void makeJsonObjectRequest（）{
showpDialog（）；
JsonObjectRequest JSONObjectReq=新的JsonObjectRequest（Method.GET，urlJsonObj，null，new Response.Listener（））{
@凌驾
公共void onResponse（JSONObject响应）{
Log.d（TAG，response.toString（））；
JSONObject phone=response.getJSONObject（“31”）.getJSONObject（“基本”）；
字符串名称=phone.getString（“title”）；
String email=phone.getString（“说明”）；
JSONObject comments=response.getJSONObject（“31”）.getJSONObject（“comments”）；
String home=comments.getString（“count”）；
JSONObject like=response.getJSONObject（“31”）.getJSONObject（“likes”）；
String mobile=like.getString（“count”）；
jsonResponse=“”；
jsonResponse+=“名称：”+Name+“\n\n”；
jsonResponse+=“电子邮件：”+Email+“\n\n”；
jsonResponse+=“Home:“+Home+”\n\n”；
jsonResponse+=“Mobile:“+Mobile+”\n\n\n”；
setText（jsonResponse）；

我需要检索所有对象，但这里我只检索一个对象（我指的是所有

node\u id

s）。我需要您的建议。 谢谢。

关于这一部分

response.getJSONObject("31")

---

您需要更改变量的

31

，并将其调用到对象的每个字段

您将获得带有键的条目

“31”

（

response.getJSONObject（“31”）

），但是，您应该迭代所有键：

 JsonObjectRequest jsonObjReq = new JsonObjectRequest(Method.GET, urlJsonObj, null, new Response.Listener<JSONObject>() {
     @Override
     public void onResponse(JSONObject response) {
         for (String key : response.keySet()) {
             JSONObject entry = response.getJSONObject(key);
             Log.d(TAG, entry.toString());

             JSONObject phone = entry.getJSONObject("basic");
             String name = phone.getString("title");
             String email = phone.getString("description");
             JSONObject comments = entry.getJSONObject("comments");
             String home = comments.getString("count");
             JSONObject like = entry.getJSONObject("likes");
             String mobile = like.getString("count");

             jsonResponse = "";
             jsonResponse += "Name: " + name + "\n\n";
             jsonResponse += "Email: " + email + "\n\n";
             jsonResponse += "Home: " + home + "\n\n";
             jsonResponse += "Mobile: " + mobile + "\n\n\n";

             txtResponse.setText(txtResponse.getText() + "\n\n" + jsonResponse); //get the old text and add it to it
         }
     } 
}

---

使用此网站，它可以帮助您从Json转换为Objects感谢您的回复。我尝试了您的代码，但我发现response.keys（）的错误“只能迭代数组或java.lang.Iterable的实例”。您可以建议吗？@srikanth Make

keys（）

keySet（）

@gogu您从哪个包导入JSONObject？

 JsonObjectRequest jsonObjReq = new JsonObjectRequest(Method.GET, urlJsonObj, null, new Response.Listener<JSONObject>() {
     @Override
     public void onResponse(JSONObject response) {
         List<String> nodeIds = new ArrayList<String>();
         for (String key : response.keySet()) {
             JSONObject entry = response.getJSONObject(key);
             nodeIds.add(enty.getJSONObject("basic").getString("node_id"));
         }
         txtResponse.setText(ListUtils.toString(nodeIds)); //from apaches commons library
     }
}