Android 如何将Json数组分配到微调器列表中？

我有一个JSON示例列表，如下所示，我尝试将其放入我的微调器中：-

[{“职业id”：0，“职业名称”：“教师”}，{“职业id”：1，“职业名称”：“企业主”}]

当我尝试应用这些代码时：-

val jsonArray = JSONArray(jsonString)

        var list = ArrayList<Occupation>()

        var x = 0
        while (x < jsonArray.length()) {
            var jsonObject = jsonArray.getJSONObject(x)

            list.add(Occupation(
                    jsonObject.getString("occupation_id"),
                    jsonObject.getString("occupation_name")
            ))
            x++
        }

        var spinnerOccupation = findViewById<Spinner>(jasiez.helloworld.jasiez.R.id.spinnerOccupation)
        // Initializing an ArrayAdapter
        val occupationAdapter = ArrayAdapter(
                this, // Context
                android.R.layout.simple_spinner_item,
                list// Array
        )

        occupationAdapter.setDropDownViewResource(android.R.layout.simple_dropdown_item_1line)
        spinnerOccupation.adapter = occupationAdapter

到

I获取错误未解析的引用：职业名称。如果我更改为列表[0]。职业名称.toList（）我将在每个下拉列表选项中显示第一个职业名称，其中包含1个字符

---

如何在这里的每个选项中获得正确的职业名称？请帮忙。谢谢。

我在处理JSon时也遇到过同样的问题。我所做的是从我的对象中重写

到字符串

。在您的情况下，您可以从Occupations对象中将

toString

重写为您的职业名称

public class Occupation {
    int occupation_id;
    String occupation_name;

    public Occupation() {
    }

    public int getOccupation_id() {
        return occupation_id;
    }

    public void setOccupation_id(int occupation_id) {
        this.occupation_id = occupation_id;
    }

    public String getOccupation_name() {
        return occupation_name;
    }

    public void setOccupation_name(String occupation_name) {
        this.occupation_name = occupation_name;
    }

    //converts your occupation_name to string
    @NonNull
    @Override
    public String toString() {
        return occupation_name;
        //or you can also add title to your occupation name by doing this
       //return "Occupation: "+ occupation_name;
    }
}

---

检查这是否对您有效。

当您使用ArrayAdapter时，您只能传递字符串列表（list），不能传递like list，请按如下所示制作列表：

    var list = ArrayList<String>()
    .......
    list.add(jsonObject.getString("occupation_name"))

var list=ArrayList（）
.......
添加（jsonObject.getString（“职业名称”））

您可以编写一个自定义适配器来保存数据列表，并覆盖getview以在微调器的textview中设置值。请看一个例子

public class Occupation {
    int occupation_id;
    String occupation_name;

    public Occupation() {
    }

    public int getOccupation_id() {
        return occupation_id;
    }

    public void setOccupation_id(int occupation_id) {
        this.occupation_id = occupation_id;
    }

    public String getOccupation_name() {
        return occupation_name;
    }

    public void setOccupation_name(String occupation_name) {
        this.occupation_name = occupation_name;
    }

    //converts your occupation_name to string
    @NonNull
    @Override
    public String toString() {
        return occupation_name;
        //or you can also add title to your occupation name by doing this
       //return "Occupation: "+ occupation_name;
    }
}

    var list = ArrayList<String>()
    .......
    list.add(jsonObject.getString("occupation_name"))