Android 当我将弹出窗口设置为外部可触摸时，错误编辑文本不会在弹出窗口中显示键盘

我的活动有一个弹出窗口，弹出窗口有编辑文本。问题是，当我将弹出窗口设置为外部可触摸时，错误编辑文本不会在android中打开弹出窗口中的键盘，我通过在弹出窗口中提供取消按钮来关闭弹出窗口。请帮忙，谢谢

 LayoutInflater inflater = (LayoutInflater)
                    getSystemService(LAYOUT_INFLATER_SERVICE);
            final View popupView = inflater.inflate(R.layout.repeat, null);
            int width = LinearLayout.LayoutParams.MATCH_PARENT;
            int height = LinearLayout.LayoutParams.WRAP_CONTENT;
            boolean focusable = false; 
            final PopupWindow popupWindow = new PopupWindow(popupView, width, height, focusable);

            // show the popup window
            // which view you pass in doesn't matter, it is only used for the window tolken
            popupWindow.showAtLocation(view, Gravity.CENTER, 0, 0);
            final LinearLayout until = popupView.findViewById(R.id.Until);
            Button pop_done = popupView.findViewById(R.id.pop_done);
            Button pop_cancel = popupView.findViewById(R.id.pop_cancel);
            dropdown = popupView.findViewById(R.id.spinner);
            final EditText repetition = popupView.findViewById(R.id.repeat_times);

• 试试这个

  LayoutInflater inflater = (LayoutInflater)
                  getSystemService(LAYOUT_INFLATER_SERVICE);
          final View popupView = inflater.inflate(R.layout.repeat, null);
          int width = LinearLayout.LayoutParams.MATCH_PARENT;
          int height = LinearLayout.LayoutParams.WRAP_CONTENT;
          final PopupWindow popupWindow = new PopupWindow(popupView, width, height);
          popupWindow.setFocusable(true);
          popupWindow.update();
          // show the popup window
          // which view you pass in doesn't matter, it is only used for the window tolken
          popupWindow.showAtLocation(v, Gravity.CENTER, 0, 0);
          popupWindow.setOutsideTouchable(false);
          final LinearLayout until = popupView.findViewById(R.id.Until);
          Button pop_done = popupView.findViewById(R.id.pop_done);
          Button pop_cancel = popupView.findViewById(R.id.pop_cancel);
          Spinner dropdown = popupView.findViewById(R.id.spinner);
          final EditText repetition = popupView.findViewById(R.id.repeat_times);
  

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当单击EditExt未运行时，您需要添加InputMethodManager尝试..我更新我的答案请检查。编辑文本正在运行，但我希望避免在触摸外部时弹出关闭…我将focusable设置为false…我可以避免关闭弹出…但edittext不会显示键盘…为什么要执行focusable false？这是另一回事可触摸且可聚焦。嘿，谢谢你的解决方案…但我尝试了使用match parent的布局并保持透明背景…在该布局内，我使用重心弹出窗口…在这种情况下，将弹出整个match parent。。。