Android 如何对每列使用Rank(),并获取顶部和底部的3个值
您好,我发现很难实现Rank()函数,下面是我的示例表Android 如何对每列使用Rank(),并获取顶部和底部的3个值,android,sqlite,Android,Sqlite,您好,我发现很难实现Rank()函数,下面是我的示例表 id category value volume 1 product1 0.4 0.5 2 product2 0.9 0.6 3 product3 0.3 0.7 4 product4 0.19 0.59 现在我想分别对“value”和“volume”列进行排名,并获得每列的前3名和后3名,我正在firefox浏览
id category value volume
1 product1 0.4 0.5
2 product2 0.9 0.6
3 product3 0.3 0.7
4 product4 0.19 0.59
现在我想分别对“value”和“volume”列进行排名,并获得每列的前3名和后3名,我正在firefox浏览器sqlmanager中测试下面的代码。但这个查询不起作用
SELECT Value, RANK()
OVER (ORDER BY Value DESC) AS xRank
FROM (SELECT Value FROM product_achievment) WHERE xRank>=3;
感谢您的帮助
排名
UNION
SELECT * FROM product_achievement ORDER BY value LIMIT 3
UNION
SELECT * FROM product_achievement ORDER BY value DESC LIMIT 3
UNION
SELECT * FROM product_achievement ORDER BY volume LIMIT 3
UNION
SELECT * FROM product_achievement ORDER BY volume DESC LIMIT 3;
排名的变通方法
:
如果您还需要排名信息,我建议创建一个带有排名的视图
:
CREATE VIEW ranked_product_achievement AS
SELECT *,
(SELECT COUNT() FROM product_achievement WHERE value<=t.value) AS r_value_a,
(SELECT COUNT() FROM product_achievement WHERE value>=t.value) AS r_value_d,
(SELECT COUNT() FROM product_achievement WHERE volume<=t.volume) AS r_volume_a,
(SELECT COUNT() FROM product_achievement WHERE volume>=t.volume) AS r_volume_d
FROM product_achievement AS t;
SELECT id, category, value, volume, r_value_a, r_volume_a
FROM ranked_product_achievement
WHERE r_value_a<=3 OR r_value_d<=3 OR r_volume_a<=3 OR r_volume_d<=3;