Warning: file_get_contents(/data/phpspider/zhask/data//catemap/4/json/14.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Arrays Mongodb:查询嵌套在数组中的json对象_Arrays_Json_Mongodb_Find - Fatal编程技术网

Arrays Mongodb:查询嵌套在数组中的json对象

Arrays Mongodb:查询嵌套在数组中的json对象,arrays,json,mongodb,find,Arrays,Json,Mongodb,Find,我是mongodb的新手,有一件事我现在无法解决: 让我们假设您有以下文档(简化): 哪个查询将返回值等于“value2”的json对象 这意味着,我需要这个json对象: { 'name' : 'test2', 'value': 'value2' } 当然,我已经尝试了很多可能的查询,但是没有一个返回正确的结果 db.test.find({'array.value':'value2'}) db.test.find({'array.value':'value2'}, {'a

我是mongodb的新手,有一件事我现在无法解决:
让我们假设您有以下文档(简化):

哪个查询将返回值等于“value2”的json对象

这意味着,我需要这个json对象:

{
    'name' :  'test2',
    'value':  'value2'
}
当然,我已经尝试了很多可能的查询,但是没有一个返回正确的结果

db.test.find({'array.value':'value2'})
db.test.find({'array.value':'value2'}, {'array.value':1})
db.test.find({'array.value':'value2'}, {'array.value':'value2'})  
有人能帮我看看我做错了什么吗?

谢谢

像这样尝试$in操作符:


db.test.find({“array.value”:{$in:[“value2”]})
使用位置运算符

db.test.find(
    { "array.value": "value2" },
    { "array.$": 1, _id : 0 }
)
    MongoClient mongoClient = new MongoClient(new ServerAddress("localhost", 27017));
    DB db = mongoClient.getDB("mydb");
    DBCollection collection = db.getCollection("test");

    DBObject unwind = new BasicDBObject("$unwind", "$array");
    DBObject match = new BasicDBObject("$match", new BasicDBObject(
            "array.value", "value2"));
    DBObject project = new BasicDBObject("$project", new BasicDBObject(
            "_id", 0).append("array", 1));

    List<DBObject> pipeline = Arrays.asList(unwind, match, project);
    AggregationOutput output = collection.aggregate(pipeline);

    Iterable<DBObject> results = output.results();

    for (DBObject result : results) {
        System.out.println(result.get("array"));
    }
输出

{ "array" : [ { "name" : "test2", "value" : "value2" } ] }
使用聚合

db.test.aggregate([
    { $unwind : "$array"},
    { $match : {"array.value" : "value2"}},
    { $project : { _id : 0, array : 1}}
])
输出

{ "array" : { "name" : "test2", "value" : "value2" } }
使用Java驱动程序

db.test.find(
    { "array.value": "value2" },
    { "array.$": 1, _id : 0 }
)
    MongoClient mongoClient = new MongoClient(new ServerAddress("localhost", 27017));
    DB db = mongoClient.getDB("mydb");
    DBCollection collection = db.getCollection("test");

    DBObject unwind = new BasicDBObject("$unwind", "$array");
    DBObject match = new BasicDBObject("$match", new BasicDBObject(
            "array.value", "value2"));
    DBObject project = new BasicDBObject("$project", new BasicDBObject(
            "_id", 0).append("array", 1));

    List<DBObject> pipeline = Arrays.asList(unwind, match, project);
    AggregationOutput output = collection.aggregate(pipeline);

    Iterable<DBObject> results = output.results();

    for (DBObject result : results) {
        System.out.println(result.get("array"));
    }

使用$elemMatch和点(.)获得所需的输出

db.getCollection('mobiledashboards').find({"_id": ObjectId("58c7da2adaa8d031ea699fff") },{ viewData: { $elemMatch : { "widgetData.widget.title" : "England" }}})

您可以在元素匹配中传递多个find对象以获得准确答案

db.test.find({'array':{$elemMatch:{value:"value2"}})

output: {'name' :  'test1','value':  'value1'}

谢谢你的帮助,但不幸的是它也不起作用。如果我在终端中运行它,它将返回整个文档