C++ 使用<；向量>；使用cin和for（）循环C++；

我的练习中有一段代码，我需要：

• 添加一名学生，其姓名、id、教育程度和3个年级
• 修改学生的分数
• 删除学生
• 显示已批准学生的列表
• 显示一份经过重新认证的学生名单
• 显示完整的列表

我已经使用向量完成了这项工作，下面是我的代码：

int resp = 0;

vector<int> ids;
vector<string> names;
vector<string> levels;
vector<double> grades1;
vector<double> grades2;
vector<double> grades3;
vector<double> average;
vector<double> approved;
vector<double> repproved;

string name, level;
int id, elim, id_delete, i=0;
double grade=0, sum=0;

do {

    cout<<"######### OPTIONS MENU #########"<<"\n\n";

    cout<<"[1] Add a student"<<"\n";
    cout<<"[2] Add grades of a student"<<"\n";
    cout<<"[3] Modify grades of a student"<<"\n";   
    cout<<"[4] Delete a student"<<"\n";
    cout<<"[5] Show approved list"<<"\n";
    cout<<"[6] Show repproved list"<<"\n";
    cout<<"[7] Show the full list"<<"\n";
    cout<<"[8] Exit"<<"\n\n";

    cin>>resp;

    switch(resp) {
        case 1:
            cout<<"Enter the student's name: \n";
            cin.sync(); cin.clear();
            getline(cin, name);
            names.push_back(name);
            cout<<"Enter the student's id: \n";
            cin>>id;
            ids.push_back(id);
            cout<<"Enter the student's school level: \n";
            cin.sync(); cin.clear();
            getline(cin, level);
            levels.push_back(level);

            cout<<"Student added";

        break;
        case 2:
            cout<<"Enter the grade 1 of the student: \n";
            cin>>grade;
            grades1.push_back(grade);
            cout<<"Enter the grade 2 of the student: \n";
            cin>>grade;
            grades2.push_back(grade);
            cout<<"Enter the grade 3 of the student: \n";
            cin>>grade;
            grades3.push_back(grade);

            cout<<"Grades added";
        break;
        case 3:
            cout<<"Enter the student's id you wish to modify grades on: \n";
            cin>>id_delete;

            for(int i=0; i<ids.size(); i++) {
                if(id_delete==ids[i]) {
                    id_delete = i;
                    break;
                }
            }

            i=id_delete;
            cout<<"Enter the new grade 1 of the student: \n";
            cin>>grade;
            grades1[i] = grade;

            cout<<"Enter the new grade 2 of the student: \n";
            cin>>grade;
            grades2[i] = grade;

            cout<<"Enter the new grade 3 of the student: \n";
            cin>>grade;
            grades3[i] = grade;

            cout<<"Grades modified\n";

        break;
        case 4:
            cout<<"Enter the student's id you wish delete: \n";
            cin>>id_delete;

            for(int i=0; i<ids.size(); i++) {
                if(id_delete==ids[i]) {
                    id_delete = i;
                    break;
                }
            }

            ids.erase (ids.begin()+(id_delete-1));
            names.erase (names.begin()+(id_delete-1));
            levels.erase (levels.begin()+(id_delete-1));
            grades1.erase (grades1.begin()+(id_delete-1));
            grades2.erase (grades2.begin()+(id_delete-1));
            grades3.erase (grades3.begin()+(id_delete-1));

            cout<<"Student deleted\n";

        break;
        case 5:
            for(i = 0; i<ids.size(); i++) {
                average[i] = (grades1[i] + grades2[i] + grades3[i])/3;
            }

            for(i = 0; i<ids.size(); i++) {
                if(average[i] >= 7 && average[i] <= 10) {
                    approved[i] = average[i];
                } else {
                        repproved[i] = average[i];
                    }

            }

            for(i = 0; i<ids.size(); i++) {
                cout<<approved[i]<<endl;
            }
        break;
        case 6:
            for(i = 0; i<ids.size(); i++) {
                cout<<repproved[i]<<endl;
            }
        break;
        case 7:
            for(i = 0; i<ids.size(); i++) {
                cout<<approved[i]<<endl;
            }

            for(i = 0; i<ids.size(); i++) {
                cout<<repproved[i]<<endl;
            }

int resp=0；
向量ID；
载体名称；
媒介水平；
病媒等级1；
病媒等级2；
病媒等级3；
向量平均；
矢量批准；
向量重证明；
字符串名称，级别；
int-id，elim，id\u-delete，i=0；
双级=0，总和=0；
做{
cout发生崩溃是因为您访问了多个向量的成员，这些向量超出了它们的端点

例如：

for(i = 0; i<ids.size(); i++) {
    average[i] = (grades1[i] + grades2[i] + grades3[i])/3;
}

for（i=0；i作为向量

vector<double> average;
vector<double> approved;
vector<double> repproved;

不如

average[i] = (grades1[i] + grades2[i] + grades3[i])/3;

和其他两个向量一样

批准和
重新批准

我希望你说得清楚。
粘贴整个代码。你知道如何调试吗？到目前为止你做了什么。当我输入5时，你的程序做的第一件事就是
average[0]=（grades1[0]+grades2[0]+grades3[0]）/3；
，但是
average
是空的，因此没有
average[0]整个代码：在多个范围内调用变量<代码> i>代码>。您应该考虑将这里声明的变量重命名为代码> int id、elIM、IDyDelphi、i＝0、，作为其他内容。主题外的建议：除非您有一个很好的理由不让我看不见，否则就要构造一个统一名称、级别、等级等的结构。让1个向量由该结构组成。例如：
struct student{int id；std:：string name；std:：string level；double grade 1；…}
和
std:：vector students；
应该可以真正简化您的簿记。
average[i] = (grades1[i] + grades2[i] + grades3[i])/3;