C# 如何在WPF工具箱图表中动态添加任意数量的线系列？

是否可以在一个工具箱图表中绘制多行，其中行号在运行时确定？与集合相比，我更喜欢使用MVVM方式绑定行。例如，下面只显示一个“LineSeries”，但如果要显示多行，该怎么办。谢谢大家!

            <ch:Chart.Series>
            <ch:LineSeries Title="{Binding Title}"
                           ItemsSource="{Binding  DataPoints}"
            IndependentValueBinding="{Binding Path=X}"
            DependentValueBinding="{Binding Path=Y}">
            </ch:LineSeries>
        </ch:Chart.Series>

---

编辑3-添加测试按钮：

XAML：

视图模型：

public class MyViewModel2
{
    public List<PointCollection> MyList { get; set; }

    public MyViewModel2()
    {
        MyList = new List<PointCollection>();
    }
}

public class MyViewModel
{
    public PointCollection MyPointCollection1 { get; set; }
    public PointCollection MyPointCollection2 { get; set; }

    public MyViewModel()
    {
        MyPointCollection1 = new PointCollection();
        MyPointCollection2 = new PointCollection();
    }
}

窗口：

    int index;
    MyViewModel2 viewModel;

    private void Window_Loaded(object sender, RoutedEventArgs e)
    {
        viewModel = new MyViewModel2();
        DataContext = viewModel;
    }

    private void button1_Click(object sender, RoutedEventArgs e)
    {
        PointCollection pc = new PointCollection();

        for (int i = 1; i <= 10; i++)
            pc.Add(new Point { X = i, Y = i * (2 + index) });

        LineSeries series1 = new LineSeries();
        series1.DependentValuePath = "Y";
        series1.IndependentValuePath = "X";
        series1.ItemsSource = pc;
        chart1.Series.Add(series1);

        viewModel.MyList.Add(pc);

        index++;
    }

    private void Window_Loaded(object sender, RoutedEventArgs e)
    {
        viewModel = new MyViewModel2();
        DataContext = viewModel;

        PointCollection pc1 = new PointCollection();
        PointCollection pc2 = new PointCollection();

        for (int i = 1; i <= 10; i++)
        {
            pc1.Add(new Point { X = i, Y = i * 2 });
            pc2.Add(new Point { X = i, Y = i * 3 });
        }

        LineSeries series1 = new LineSeries();
        series1.DependentValuePath = "Y";
        series1.IndependentValuePath = "X";
        series1.ItemsSource = pc1;
        chart1.Series.Add(series1);

        viewModel.MyList.Add(pc1);

        LineSeries series2 = new LineSeries();
        series2.DependentValuePath = "Y";
        series2.IndependentValuePath = "X";
        series2.ItemsSource = pc2;
        chart1.Series.Add(series2);

        viewModel.MyList.Add(pc2);
    }

    private void Window_Loaded(object sender, RoutedEventArgs e)
    {
        viewModel = new MyViewModel();
        DataContext = viewModel;

        for (int i = 1; i <= 10; i++)
        {
            viewModel.MyPointCollection1.Add(new Point { X = i, Y = i * 2 });
            viewModel.MyPointCollection2.Add(new Point { X = i, Y = i * 3 });
        }
    }

private void Window\u已加载（对象发送方，路由目标）
{
viewModel=新的MyViewModel（）；
DataContext=viewModel；
对于（int i=1；感谢您的回复，但我的问题是我不知道将有多少个lineSeries，因此我无法定义MyPointCollection#和lineSeries的固定数量。请参见编辑2。请参见编辑3-添加了一个测试按钮。@user2391685您对此有任何后续问题吗？
<Grid>
    <chartingToolkit:Chart Margin="0" Title="Chart Title">
        <chartingToolkit:LineSeries DependentValuePath="Y" IndependentValuePath="X" ItemsSource="{Binding MyPointCollection1}"/>
        <chartingToolkit:LineSeries DependentValuePath="Y" IndependentValuePath="X" ItemsSource="{Binding MyPointCollection2}"/>
    </chartingToolkit:Chart>
</Grid>

public class MyViewModel
{
    public PointCollection MyPointCollection1 { get; set; }
    public PointCollection MyPointCollection2 { get; set; }

    public MyViewModel()
    {
        MyPointCollection1 = new PointCollection();
        MyPointCollection2 = new PointCollection();
    }
}

    private void Window_Loaded(object sender, RoutedEventArgs e)
    {
        viewModel = new MyViewModel();
        DataContext = viewModel;

        for (int i = 1; i <= 10; i++)
        {
            viewModel.MyPointCollection1.Add(new Point { X = i, Y = i * 2 });
            viewModel.MyPointCollection2.Add(new Point { X = i, Y = i * 3 });
        }
    }