从C#WinForm将数据发布到PHP页面

从C#WinForm将数据发布到PHP页面,c#,php,winforms,C#,Php,Winforms,我有一个winForms NET3.5SP1应用程序,想将数据发布到PHP页面 我还将以JSON的形式传递它,但我想先让它直接工作 代码如下: Person p = new Person(); p.firstName = "Bill"; p.lastName = "Gates"; p.email = "asdf@hotmail.com"; p.deviceUUID = "abcdefghijklmnopqrstuvwxyz"; JavaScrip

我有一个winForms NET3.5SP1应用程序,想将数据发布到PHP页面

我还将以JSON的形式传递它,但我想先让它直接工作

代码如下:

    Person p = new Person();
    p.firstName = "Bill";
    p.lastName = "Gates";
    p.email = "asdf@hotmail.com";
    p.deviceUUID = "abcdefghijklmnopqrstuvwxyz";

    JavaScriptSerializer serializer = new JavaScriptSerializer();
    string s;
    s = serializer.Serialize(p);
    textBox3.Text = s;
    // s = "{\"firstName\":\"Bill\",\"lastName\":\"Gates\",\"email\":\"asdf@hotmail.com\",\"deviceUUID\":\"abcdefghijklmnopqrstuvwxyz\"}"
    HttpWebRequest request = (HttpWebRequest)WebRequest.Create("http://www.davemateer.com/ig/genius/newuser.php");
    //WebRequest request = WebRequest.Create("http://www.davemateer.com/ig/genius/newuser.php");
    request.Method = "POST";
    request.ContentType = "application/x-www-form-urlencoded";
    //byte[] byteArray = Encoding.UTF8.GetBytes(s);
    byte[] byteArray = Encoding.ASCII.GetBytes(s);
    request.ContentLength = byteArray.Length;
    Stream dataStream = request.GetRequestStream();
    dataStream.Write(byteArray, 0, byteArray.Length);
    dataStream.Close ();

    WebResponse response = request.GetResponse();
    textBox4.Text = (((HttpWebResponse)response).StatusDescription);
    dataStream = response.GetResponseStream ();

    StreamReader reader = new StreamReader(dataStream);
    string responseFromServer = reader.ReadToEnd ();
    textBox4.Text += responseFromServer;

    reader.Close ();
    dataStream.Close ();
    response.Close ();
PHP5.2代码为:

<?php
echo "hello world";
var_dump($_POST);
?>

有什么想法吗?我希望它返回我刚刚传递的值,以证明我可以从服务器端访问数据。

我认为您需要正确编码并发送实际的帖子内容。看起来您只是在序列化为JSON,PHP不知道如何处理它(即,它不会将其设置为
$\u POST
值)

这将在PHP集中获得
$\u POST
变量。稍后,当您切换到JSON时,您可以执行以下操作:

string postData = "json=" + HttpUtility.UrlEncode(serializer.Serialize(p) );
并从PHP抓取:

$json_array = json_decode($_POST['json']);
string postData = "json=" + HttpUtility.UrlEncode(serializer.Serialize(p) );
$json_array = json_decode($_POST['json']);