C# System.InvalidCastException:&x27；指定的强制转换无效。'；

我正在尝试使用memorystream、filestream和struct读取二进制文件，代码如下：

BinaryFormatter formatter = new BinaryFormatter();
MemoryStream mStream = new MemoryStream();
byte[] buffer = null;
long numBytes = new FileInfo(filename1).Length;
FileStream fs = new FileStream(filename1, FileMode.Open, FileAccess.Read);
BinaryReader br = new BinaryReader(fs);
buffer = br.ReadBytes((int)numBytes);
mStream.Write(buffer, 0, buffer.Length);
mStream.Position = 0;
GameSaved newdata = (GameSaved)formatter.Deserialize(mStream);
mStream.Close();
fs.Close();
fs.Dispose();
mStream.Dispose();

GameSaved

结构如下所示：

[Serializable]
struct GameSaved
{
    public int Num_Of_Saved_Game;
    public string[] Name_Of_Saved_Game;
}

但是代码抛出了一个错误

System.InvalidCastException:'指定的强制转换无效。'

编辑：这是我保存

GameSaved

struct的方式：

buffer = null;
formatter = new BinaryFormatter();
mStream = new MemoryStream();
formatter.Serialize(mStream, newdata);
buffer = mStream.ToArray();
mStream.Close();
filename = "name.sav";
curFile = @"c:\C#\Try_To_Save_MS\Try_To_Save_MS\bin\Debug\name.sav";

if (File.Exists(curFile))
    File.Delete(curFile);

fs = new FileStream(filename, FileMode.Create, FileAccess.Write);
fs.Write(buffer, 0, (int)buffer.Length);
fs.Dispose();
mStream.Dispose();

谁能告诉我解决问题的方法吗

---

致以最诚挚的问候

您应该使用BinaryFormatter.Serialize方法来序列化对象。在您的代码中，您编写了一个缓冲区，但这可能不起同样的作用

可以用这种方式编写数据序列化的示例

GameSaved reloaded = new GameSaved();
void Main()
{
    GameSaved game = new GameSaved();
    game.Num_Of_Saved_Game = 2;
    game.Name_Of_Saved_Game = new string[] {"game1", "game2"};

    Serialize(@"e:\temp\serialize.bin", game);
    Deserialize(@"e:\temp\serialize.bin");

    Console.WriteLine("Games:" + reloaded.Num_Of_Saved_Game);
    foreach(string s in reloaded.Name_Of_Saved_Game)
        Console.WriteLine(s);
}

void Deserialize(string filename1)
{
    BinaryFormatter formatter = new BinaryFormatter();
    using(FileStream fs = new FileStream(filename1, FileMode.Open, FileAccess.Read))
        reloaded = (GameSaved)formatter.Deserialize(fs);
}
void Serialize(string filename1, GameSaved game)
{
    BinaryFormatter formatter = new BinaryFormatter();
    using (FileStream fs = new FileStream(filename1, FileMode.OpenOrCreate, FileAccess.Write))
        formatter.Serialize(fs, game);

}
[Serializable]
struct GameSaved
{
    public int Num_Of_Saved_Game;
    public string[] Name_Of_Saved_Game;
}

---

抛出异常的是哪一行<代码>GameSaved newdata=（GameSaved）？这是一行“GameSaved newdata=（GameSaved）formatter.Deserialize（mStream）；”可能在序列化GameSaved实例的部分出现了问题。您可以添加该代码吗？请开始使用（）。所有这些.Close（）/.Dispose（）都让我非常担心应用程序的其余部分。当您使用BinaryFormatter时，这是一个相当标准的灾难。它非常聪明，并且确切地知道使用了哪个GameSaved声明。不仅是它的名称空间名称和类型名称以及它有哪些成员，还包括它来自哪个程序集。Kaboom，当您在回读时不使用完全相同的程序集时。因此，您可能犯的一个基本错误是重新声明结构。实际上，您必须将它放在一个类库中，在编写文件的代码和读取文件的代码中都使用该类库。