Java SpringREST-手动解析@RequestBody中的JSON属性
我有实体类:Java SpringREST-手动解析@RequestBody中的JSON属性,java,json,spring,rest,jackson,Java,Json,Spring,Rest,Jackson,我有实体类: @Entity @Table(name="person") public class Person implements Serializable { @Id @Column(unique=true) private int id; private String title; // getter, setter, constructor,... } 在控制器中: @RequestMapping(value="/get/{id}", metho
@Entity
@Table(name="person")
public class Person implements Serializable {
@Id @Column(unique=true)
private int id;
private String title;
// getter, setter, constructor,...
}
在控制器中:
@RequestMapping(value="/get/{id}", method=RequestMethod.GET)
public @ResponseBody Person getPerson(@PathVariable int id) {
return personManager.findById(id);
}
@RequestMapping(value="/add", method=RequestMethod.POST)
public @ResponseBody void addPerson(@RequestBody Person person) {
String log = parse_json_from_input("log"); // How can I do it?
// do something with log
personManager.save(person);
}
我想用JSON发送额外的参数并对其进行解析。若我执行下面的命令,我会得到Person实体,这是正常的。但是我需要在addPerson
方法中获取log
属性,以用于其他用途
curl -X POST -H "Content-Type: application/json" -H "Accept: application/json" \
-d '{"title":"abc","log":"message..."}' http://localhost:8080/test/add
如何解析它?使用SpringRestTempalge
RestTemplate restTemplate = new RestTemplate();
restTemplate.getMessageConverters().add(new MappingJackson2HttpMessageConverter());
Person person = get some where
result = restTemplate.postForObject("http://localhost:8080/test/add", Person, Person.class);
使用HttpURLConnection
public class Test {
public static void main(String[] args) {
try {
URL url = new URL("http://localhost:8080/test/add");
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setDoOutput(true);
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "application/json");
OutputStream outputStream = conn.getOutputStream();
String requestMessage = get your preson json string
outputStream.write(requestMessage.getBytes());
outputStream.flush();
if (conn.getResponseCode() != HttpURLConnection.HTTP_OK) {
throw new RuntimeException("Failed : HTTP error code : " + conn.getResponseCode());
}
BufferedReader br = new BufferedReader(new InputStreamReader(conn.getInputStream()));
String output;
while ((output = br.readLine()) != null) {
System.out.println(output);
}
conn.disconnect();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
}
希望您已经有了Jackson JSON依赖项 你可以在这里找到它: 我将尝试以下代码:
ObjectMapper mapper = new ObjectMapper();
@RequestMapping(value="/add", method=RequestMethod.POST)
public @ResponseBody void addPerson(@RequestBody String json) {
ObjectNode node = mapper.readValue(json, ObjectNode.class);
if (node.get("log") != null) {
String log = node.get("log").textValue();
// do something with log
node.remove("log"); // !important
}
Person person = mapper.convertValue(node, Person.class);
personManager.save(person);
}
这就应该做到了
确保检查并删除Person POJO中没有的任何“额外”字段