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Java 对OneToMany属性值休眠条件或子查询_Java_Hibernate_Criteria - Fatal编程技术网

Java 对OneToMany属性值休眠条件或子查询

Java 对OneToMany属性值休眠条件或子查询,java,hibernate,criteria,Java,Hibernate,Criteria,我的应用程序的一个组件记录用户使用http URL发送的参数。映射如下所示: public class ActivityLog { @Column(name = "id") private Long id; @OneToMany(mappedBy="activityLog", fetch = FetchType.LAZY, cascade = CascadeType.ALL) protected List<ActivityLogParameter>

我的应用程序的一个组件记录用户使用http URL发送的参数。映射如下所示:

public class ActivityLog {

    @Column(name = "id")
    private Long id;

    @OneToMany(mappedBy="activityLog", fetch = FetchType.LAZY, cascade = CascadeType.ALL)
    protected List<ActivityLogParameter> activityLogParameters = new ArrayList<ActivityLogParameter>();
}

public class ActivityLogParameter {

    @Column(name = "id")
    private Long id;

    @Column(name = "key", length=10)
    protected String key;

    @Column(name = "value", length=50)
    protected String value;

    @ManyToOne(fetch = FetchType.LAZY, cascade={CascadeType.MERGE})
    @JoinColumn(name="activity_log_id")
    protected ActivityLog activityLog;
}
但我被困在这里了。我试着在上面添加像distinct和group by这样的投影,但这还不足以得到正确的结果

我还尝试将此条件用作子条件,以便计算任何ActivityLog的行数,并仅保留count*=2的记录所有参数都与条件匹配,但我找不到如何使用子查询

你对如何解决上述问题有什么想法?在SQL中,我会这样做:

Criteria criteria = getCurrentSession().createCriteria(ActivityLog.class, "al");
// create alias
criteria = criteria.createAlias("activityLogParameters", "alp",JoinFragment.LEFT_OUTER_JOIN);

// create transformer to avoid duplicate results
criteria = criteria.setResultTransformer(CriteriaSpecification.DISTINCT_ROOT_ENTITY);
criteria = criteria.setFetchMode("al.activityLogParameters", FetchMode.SELECT);

//filters
criteria = criteria.add(Restrictions.or(Restrictions.eq("alp.value", UValue), Restrictions.ne("alp.key", "L")));
criteria = criteria.add(Restrictions.or(Restrictions.eq("alp.value", LValue), Restrictions.ne("alp.key", "U")));
select activity_log_id from (
    select count(*) as ct, activity_log_id 
    from activity_log_parameter alp inner join activity_log al on alp.activity_log_id=al.id 
    where (alp.value='visitor' or alp.key<>'U') 
        and (alp.value='room1' or alp.key<>'L') 
    group by activity_log_id
) as subq
where subq.ct = 2

谢谢

使用子查询解决

DetachedCriteria subquery = DetachedCriteria.forClass(ActivityLogParameter.class, "alp")
        .createAlias("activityLog", "al",JoinFragment.LEFT_OUTER_JOIN)
        .setProjection(Projections.projectionList()
                .add(Projections.count("id"), "alpId"));

subquery = subquery.add( Property.forName("al.id").eqProperty("mainAl.id") );

subquery = subquery.add(Restrictions.or(Restrictions.eq("alp.value", UValue), Restrictions.ne("alp.key", "L")));
subquery = subquery.add(Restrictions.or(Restrictions.eq("alp.value", LValue), Restrictions.ne("alp.key", "U")));

Criteria criteria = getCurrentSession().createCriteria(type, "mainAl");

criteria = criteria.add(Subqueries.eq(new Long(2), subquery));