如何在Java中向多个输出文件写入不同的值？

我有下面的Java8代码，它创建了一个文件fine（文件中的内容是一行单独的文本）。改变代码的最好方法是什么，这样我就可以得到三个独立的文本文件

String os = System.getProperty("os.name");
String jv = System.getProperty("java.version");
String userfolder = System.getProperty("user.home");

try (Writer writer = new BufferedWriter(new OutputStreamWriter(
                new FileOutputStream(userfolder + "opsys.txt"), "utf-8")))
                {
                 writer.write((String) os);
                } catch (UnsupportedEncodingException e) 
                {
                e.printStackTrace();
                } catch (FileNotFoundException e) 
                {
                e.printStackTrace();
                } catch (IOException e) 
                {
                e.printStackTrace();
                }

我试图实现的输出：

• 3个文本文件
  • 命名为opsys.txt、version.txt和userhome.txt
  • 每个文件都包含相关的System.getProperty答案

---

您可以将写入文件的所有功能放在单独的方法中，例如：

private void writeFile(String fileName, String content) {

    try (Writer writer = new BufferedWriter(new OutputStreamWriter(
            new FileOutputStream(fileName), "utf-8")))
    {
        writer.write((String) content);
    } catch (UnsupportedEncodingException e)
    {
        e.printStackTrace();
    } catch (FileNotFoundException e)
    {
        e.printStackTrace();
    } catch (IOException e)
    {
        e.printStackTrace();
    }
}

String os = System.getProperty("os.name");
String jv = System.getProperty("java.version");
String userfolder = System.getProperty("user.home");

//Here you call the writeFile method the number of time that you need:
writeFile(userfolder + "opsys.txt", os);
....

在此之后，您以前的代码将类似于：

private void writeFile(String fileName, String content) {

    try (Writer writer = new BufferedWriter(new OutputStreamWriter(
            new FileOutputStream(fileName), "utf-8")))
    {
        writer.write((String) content);
    } catch (UnsupportedEncodingException e)
    {
        e.printStackTrace();
    } catch (FileNotFoundException e)
    {
        e.printStackTrace();
    } catch (IOException e)
    {
        e.printStackTrace();
    }
}

String os = System.getProperty("os.name");
String jv = System.getProperty("java.version");
String userfolder = System.getProperty("user.home");

//Here you call the writeFile method the number of time that you need:
writeFile(userfolder + "opsys.txt", os);
....

---

使用此方法，您可以创建所需的任何文件。

您可以创建一个简单的方法，如下所示，该方法将文件名和环境变量名作为输入参数：

public void createAndWriteFile(String fileNmae, String envName) {
        String content = System.getProperty(envName);
        String userfolder = System.getProperty("user.home");
        try (Writer writer = new BufferedWriter(new OutputStreamWriter(
                        new FileOutputStream(userfolder + fileNmae), "utf-8"))) {
         writer.write(content);
        } catch (IOException e) {
            e.printStackTrace();
        } 
    }

现在，调用上述方法3次，如下所示：

String os = System.getProperty("os.name");
createAndWriteFile("opsys.txt",os);
String javaVersion = System.getProperty("java.version");
createAndWriteFile("version.txt",javaVersion);
String userHome = System.getProperty("user.home");
createAndWriteFile("userhome.txt",userHome);

---

将编写器代码带到一个函数，该函数接受2个参数，即您要保存的字符串和文件名。@Dez，我感谢您的回复，尽管对某些人来说可能看起来很简单-这意味着我现在可以继续学习了！谢谢我只是想确认一下，这对我是有效的。再次感谢曼纽尔！