Warning: file_get_contents(/data/phpspider/zhask/data//catemap/4/video/2.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Java xuggler视频剪辑_Java_Video_Video Processing_Xuggler - Fatal编程技术网

Java xuggler视频剪辑

Java xuggler视频剪辑,java,video,video-processing,xuggler,Java,Video,Video Processing,Xuggler,我有两次(longtime1,time2;),输入文件和输出目录。我想将视频从time1剪切到time2并保存在outdir中,有人能提供一个简单的工作代码示例吗 public class CutAndSaveVideoTest { public static void main(String[] args) { long timeStart=0, timeEnd=0; String filename = "C:\\Documents and Set

我有两次(longtime1,time2;),输入文件和输出目录。我想将视频从time1剪切到time2并保存在outdir中,有人能提供一个简单的工作代码示例吗

public class CutAndSaveVideoTest {

    public static void main(String[] args) {

        long timeStart=0, timeEnd=0;

        String filename = "C:\\Documents and Settings\\...\\File.avi"; 
        String outDir = "C:\\Documents and Settings\\...";
        String outFileName = "Test.mp4";
        String outDirFileName = (outDir +"\\" +outFileName );

        IContainer container = IContainer.make(); 


        if (container.open(filename, IContainer.Type.READ, null) < 0){
            throw new IllegalArgumentException("could not open file: " + filename);
        }

    }

}
公共类CutAndSaveVideoTest{
公共静态void main(字符串[]args){
longtimestart=0,timeEnd=0;
String filename=“C:\\Documents and Settings\\…\\File.avi”;
String outDir=“C:\\Documents and Settings\\…”;
字符串outFileName=“Test.mp4”;
字符串outDirFileName=(outDir+“\\”+outFileName);
IContainer容器=IContainer.make();
if(container.open(filename,IContainer.Type.READ,null)<0){
抛出新的IllegalArgumentException(“无法打开文件:+filename”);
}
}
}

您是否尝试过任何东西和/或有不完整的东西要显示?添加了一点代码,但没有太多