Java 在由标记分隔的一行中返回多个值的Web服务

我需要构建一个从数据库返回多行的web服务，每行应该包含几个由标记分隔的字段。我使用Netbeans创建了这个ws，它在glassfish服务器上运行。我只返回了包含字符串的标记行，字符串由连接的值字段组成。你能就如何修改我的报税表给我一些建议吗

现在，我的web服务返回如下所示：

      <?xml version="1.0" encoding="UTF-8"?><S:Envelope xmlns:S="http://schemas.xmlsoap.org/soap/envelope/">
    <S:Body>
        <ns2:extractCSResponse xmlns:ns2="http://ws/">
            <ROW xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:type="xs:string"><Firstname>Mark</Firstname><Lastname>Thomas</Lastname><ID>1112546</ID></ROW>
            <ROW xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:type="xs:string"><Firstname>Mike</Firstname><Lastname>Jackson</Lastname><ID>1112547</ID></ROW>
        </ns2:extractCSResponse>
    </S:Body>
</S:Envelope>

我的报税表需要如下所示：

<S:Body>
        <ns2:extractCSResponse xmlns:ns2="http://ws/">
            <ROWS>
                <ROW>
                    <Firstname>Mark</Firstname>
                    <Lastname>Thomas</Lastname>
                    <IDname>1112546</IDname>
                </ROW>
                <ROW>
                    <Firstname>Mike</Firstname>
                    <Lastname>Jackson</Lastname>
                    <IDname>1112547</IDname>
                </ROW>
            </ROWS>
        </ns2:extractCSResponse>
    </S:Body>

Java代码如下：

@WebService(serviceName = "GetCS2")
@Stateless()
public class GetCS2 {

    /**
     * This is a sample web service operation
     */
    @WebMethod(operationName = "extractCS")
    @WebResult(name = "ROW")
    public List extractCS()
    {
        List l = new ArrayList();

        //username and password for database connection
        String userName = "username";
        String password = "password";

              //db connection
            try
            {
                Class.forName("com.microsoft.sqlserver.jdbc.SQLServerDriver");

                String url = "jdbc:sqlserver://172.19.125.222:1433"+";databaseName=Test";
                Connection con = DriverManager.getConnection(url, userName, password);

                Statement stmt = con.createStatement();
                ResultSet rs = stmt.executeQuery("select * from list");

                //loop through selection
                while(rs.next())
                {               
                    l.add("<Firstname>" + rs.getString("fn") + "</Firstname>" + "<Lastname>" + rs.getString("ln") + "</Lastname>" + "<IDname>" + rs.getDate("ID") + "</ID>");
                }

                //close connections
                stmt.close();
                rs.close();
                con.close();

            } catch(SQLException e)
            {
                System.out.println("SQL Exception: " + e.toString());
            }
            catch(ClassNotFoundException cE)
            {
                System.out.println("Class Not Found Exception: " + cE.toString());
            }

            return l;

    }
}

编辑以显示基本示例，以防有一天链接不再包含此信息

---

我通常试图通过连接字符串来避免构建xml。这很容易出错，可能包含无效的xml数据，如果名称包含该数据会怎么样&或者我用一个简单的示例编辑了我的答案。希望对你有帮助谢谢！我以我想要的方式成功地返回了XML。基本上，我必须创建一个新的Person类，并且必须使用诸如：XmlElement、XmlAttribute和XmlSeeAllimport javax.xml.bind.annotation.*。我忘了提到我还返回了一个列表，就像你说的那样。谢谢

@XmlRootElement(name = "Person")
public class Person{
   private String firstName;
   private String lastName;
   private String idName;

  ....
}

@XmlRootElement(name = "PersonWrapper")
public class PersonWrapper{
   private List<Person> persons;

   @XmlElementWrapper(name = "PersonList")
   @XmlElement(name = "Person")
   public List getPersons(){
      return persons;
   }
   ....
}

List<Person> personList=new ArrayList<Person>();
while(rs.next())
{               
    personList.add(new Person(rs.getString("fn"),rs.getString("lastName"),...));
}

PersonWrapper pw=new PersonWrapper();
pw.setPersons(personList);

JAXBContext context = JAXBContext.newInstance(PersonWrapper.class);
Marshaller m = context.createMarshaller();
m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

//write to system.out or any other OutputStream (ByteArrayOutputStream)
m.marshal(pw, System.out); 

//OR write to xml file
m.marshal(pw, new File("person.xml"));