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Java 数据库不会显示结果吗?_Java_Database_Jframe - Fatal编程技术网

Java 数据库不会显示结果吗?

Java 数据库不会显示结果吗?,java,database,jframe,Java,Database,Jframe,在我的Java程序中,运行Addplaylist.Java文件时遇到问题。它打开的很好…但是对于我来说,要想添加一个播放列表,我需要数据库中每个成员的名字 我已经输入了一些System.out.println(“”)来检查我在文件中的位置,出于某种原因,我只在addPlaylist()GUI中输入了它。我试着调试它并找到错误,但我找不到 正在从主GUI调用此文件-我知道数据库中有值,并且连接正在工作,因为我在另一个文件中使用了它 这是我的addPlaylist.java: package GUI

在我的Java程序中,运行
Addplaylist.Java
文件时遇到问题。它打开的很好…但是对于我来说,要想添加一个播放列表,我需要数据库中每个
成员的名字

我已经输入了一些
System.out.println(“”)来检查我在文件中的位置,出于某种原因,我只在
addPlaylist()GUI中输入了它。我试着调试它并找到错误,但我找不到

正在从
主GUI调用此文件
-我知道数据库中有值,并且连接正在工作,因为我在另一个文件中使用了它

这是我的
addPlaylist.java

package GUI;

import DBconnection.connection;


import java.awt.Container;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.sql.Statement;
import java.util.logging.Level;
import java.util.logging.Logger;
import javax.swing.ButtonGroup;
import javax.swing.JButton;
import javax.swing.JComboBox;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.JPanel;
import javax.swing.JRadioButton;
import javax.swing.JTextArea;
import javax.swing.JTextField;

/**
 *
 * @author james
 */
public class addPlaylist extends JFrame implements ActionListener{
    private Container mainCon = this.getContentPane();
    private JPanel formPanel = new JPanel();
    private JPanel paidPanel = new JPanel();

    /*ALL USER INPUT FIELDS*************************/
    //Buttons
    private static JButton submitPlaylist = new JButton("Add Playlist");

    /*TEXT FIELDS BOXES *******************************/
    private JLabel lblPlaylistName = new JLabel("Playlist Name: ");
    private JTextField txtPlaylistName = new JTextField("", 15);
    /*TEXT FIELDS BOXES *******************************/

    /*COMBO BOXES *******************************/
    private JLabel lblNames = new JLabel();
    private JComboBox comNames = new JComboBox();
    /*COMBO BOXES *******************************/

    /*DECLARED VARIABLES ****************************/
    //    private String membersData = "";
    /*DECLARED VARIABLES ****************************/

    public addPlaylist(){
        super("Add a Playlist");
        this.setBounds(400, 500, 315,400);
        mainCon.add(formPanel);

        /** BEGINNING OF FORM ************/
        formPanel.add(lblPlaylistName);
        formPanel.add(txtPlaylistName);

        //Combobox (Names)
        formPanel.add(lblNames);
        formPanel.add(comNames);
        //comNames.addActionListener(this);

        //txtPlaylistName.addActionListener(this);
        System.out.println("In add playlist");
    }

    public void actionPerformed(ActionEvent action) {
        System.out.println("In Action Performed");
        /**ADD DATABASE CONNECTIONS*****************/
        /****** Set the default code - needed for SQL statements *************/
        Connection conDB = null;
        Statement stmt = null;
        ResultSet membersData = null;

        /** GET MYSQL DETAILs ---------**/
        String url = connection.geturl();
        String username = connection.getUsername();
        String password = connection.getPassword();


        try{
            System.out.println("In Try Statement");
             /****** DEFAULT MYSQL DRIVERS **************************/
            //load the MYSQL driver
                Class.forName(connection.getDriver());
                conDB = DriverManager.getConnection(url, username, password);
                //create statement
                stmt = conDB.createStatement();
            /****** DEFAULT MYSQL DRIVERS **************************/

            String sqlSelect = "SELECT membId, name, memberType FROM members";
            membersData = stmt.executeQuery(sqlSelect);
            System.out.println("After executed");


            while(membersData.next()){
//                comNames.addItem(membersData.getString("name"));
                System.out.println("In while loop");
                String membId = membersData.getString("membId");
                System.out.println(membId);

     //            System.out.println(membersData.getString("name"));
     //            System.out.println(membersData.getString("memberType"));
            }
            //membersData.close();
        }
        catch(SQLException er){
            System.out.println("Error was: " + er);
        } catch (ClassNotFoundException ex) {
            System.out.println("SECOND ERROR: " + ex);
        }
    }  
}

因此,为了解决这个问题,我将显示组合框所需的所有代码放入名为
showCombo()
的函数中,包括
数据库连接和结果集等。然后我在
addPlaylist(){}
方法中调用了
showCombo()

像这样:

public void showCombo(){
            /****** Set the default code - needed for SQL statements *************/
        Connection conDB = null;
        Statement stmt = null;
        ResultSet membersData = null;



        /** GET MYSQL DETAILs ---------**/
        String url = connection.geturl();
        String username = connection.getUsername();
        String password = connection.getPassword();


        try{
            System.out.println("In Try Statement");
             /****** DEFAULT MYSQL DRIVERS **************************/
            //load the MYSQL driver
                Class.forName(connection.getDriver());
                conDB = DriverManager.getConnection(url, username, password);
                //create statement
                stmt = conDB.createStatement();
            /****** DEFAULT MYSQL DRIVERS **************************/

            String sqlSelect = "SELECT membId, name, memberType FROM members";
            membersData = stmt.executeQuery(sqlSelect);
            System.out.println("After executed");



            while(membersData.next()){
                comNames.addItem(membersData.getString("name"));
//                System.out.println("In while loop");
//                String membId = membersData.getString("membId");
//                System.out.println(membId);

//                System.out.println(membersData.getString("name"));
//                System.out.println(membersData.getString("memberType"));
            }
            //membersData.close();
        }
        catch(SQLException er){
            System.out.println("Error was: " + er);
        } catch (ClassNotFoundException ex) {
            System.out.println("SECOND ERROR: " + ex);
        }
        }

你需要为你的JFrame设置一个动作监听器,在addPlaylist()构造函数->中设置按钮的动作监听器(submitPlaylist.addActionListener(this);@Praveen-我已经添加了一个答案。你知道为什么我的
JComboBox
中有两项被选中了吗?每个项目有两个副本,如果你点击其中一个,那么另一个会被勾选?!为JComboBox 1创建一个ItemListener,并在第一个记录更新时更新下一个记录。感谢您的帮助:)@Praveen-但我意识到,在数据库中,我有两个相同的记录:S出于某种原因,每次您单击一个与另一个同名的记录时,它也会勾选另一个!