Java 要在另一个实体中引用的复合键的一个Id 表1只有两列组成复合键 正在生成表2 id列 我提供的表1的一个属性的值，以及第二个属性的值，我需要它来获取表2的生成值。 这是我到目前为止所拥有的-

复合主键：

public class PKClass implements Serializable
{
    private static final long serialVersionUID = -2092390836751020965L;
    public PKClass(){}
    public PKClass(long actId, long actAttId){
        this.actvId = actId;
        this.actvAtId = actAttId;
    }

    private long actvId;
    private long actvAtId;
    // getters, setters, equals, hashcode
}

实体类别1：

@Entity @Table(name = "Table1")
@IdClass(PKClass.class)
public class AtLinkData implements Serializable
{
    @Id @Column(name = "ACT_ID", nullable = false)
    private long actvId;
    @Id @Column(name = "ACT_AT_ID")
    private long actvAtId;
    @OneToOne(cascade = CascadeType.ALL, fetch = FetchType.EAGER, , mappedBy = "atLinkData")
    @JoinColumn(name = "ACT_AT_ID")
    private AtData atData;
    // getters, setters
}

实体类别2：

@Entity @Table(name = "Table2")
public class AtData implements Serializable
{
    @TableGenerator(name = "somename", table = "sometable", pkColumnName = "somecolumn", valueColumnName = "valuename", pkColumnValue = "Table2", allocationSize = 1)
    @Id @GeneratedValue(strategy = GenerationType.TABLE, generator = "somename")
    @Column(name = "ACT_AT_ID")
    private Long id;
    // other variables
    @OneToOne(fetch = FetchType.LAZY)
    @JoinColumn(name = "ACT_AT_ID")
    private AtLinkData atLinkData;
    // getters setters
}

我一直在尝试不同的事情，但通过上面的代码，我得到了错误：

Caused by: org.hibernate.MappingException: broken column mapping for: atLinkData.id of: com.test.database.AtData

@OneTONE（mappedBy=“otherInfo”） 使用

JoinColumns

注释而不是

JoinColumns

@OneToOne(fetch = FetchType.LAZY)
@JoinColumns({
    @JoinColumn(name = "ACTVID", referencedColumnName = "ACTVID"),
    @JoinColumn(name = "ACTVATID", referencedColumnName = "ACTVATID")
})
private AtLinkData atLinkData;  

数据库表的

AtData

实体您必须添加两个外键列

ACTVID

和

ACTVATID

更新

如果无法在

表2中添加新列，请使用
AtData
实体中的
mappedBy
属性，而不是
AtLinkData
。尝试如下

AtLinkData.java

@OneToOne(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
@JoinColumn(name = "ACT_AT_ID")
private AtData atData;

@Id
@GeneratedValue(generator = "foreignGenerator")
@org.hibernate.annotations.GenericGenerator(name = "foreignGenerator", strategy = "foreign", parameters = @Parameter(name = "property", value = "atData"))
@Column(name = "ACT_AT_ID")
private long actvAtId;

@OneToOne(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
@JoinColumn(name = "ACT_AT_ID",insertable=false,updatable=false)
private AtData atData;
// getters, setters

AtData.java

@OneToOne(fetch = FetchType.LAZY, mappedBy="atData")
private AtLinkData atLinkData;

@OneToOne(fetch = FetchType.LAZY, mappedBy="atData")
private AtLinkData atLinkData;

我是这样解决的：

AtLinkData.java

@OneToOne(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
@JoinColumn(name = "ACT_AT_ID")
private AtData atData;

@Id
@GeneratedValue(generator = "foreignGenerator")
@org.hibernate.annotations.GenericGenerator(name = "foreignGenerator", strategy = "foreign", parameters = @Parameter(name = "property", value = "atData"))
@Column(name = "ACT_AT_ID")
private long actvAtId;

@OneToOne(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
@JoinColumn(name = "ACT_AT_ID",insertable=false,updatable=false)
private AtData atData;
// getters, setters

AtData.java

@OneToOne(fetch = FetchType.LAZY, mappedBy="atData")
private AtLinkData atLinkData;

@OneToOne(fetch = FetchType.LAZY, mappedBy="atData")
private AtLinkData atLinkData;

感谢您的帮助。
我无法在表2中添加另一列，它是一个现有表。按照建议更改了代码，现在代码失败，因为PKClass中的actvAtId为null，因此hashcode（）失败。我应该在AtLinkData中实例化PKClass吗？据我所知，我想不是现在，如果我单独尝试，实体AtData将被成功持久化。