Javascript 将JSON填充并格式化到Google工作表中
提前感谢任何能够在这方面帮助我的人。几天来,我一直在努力使这项工作顺利进行,但我对这方面的了解还不够,无法通过示例来理解 我开发了一个Android应用程序,可以在实时数据库中下订单。每个订单都有自己的ID,该ID由应用程序生成。我希望在运行代码并根据列标题进入正确的列时,每个订单都显示在一行中。我发现这似乎完全符合我的需要(相同的JSON结构),但当我尝试重新调整用途时,它不起作用。以下是我所拥有的:Javascript 将JSON填充并格式化到Google工作表中,javascript,json,google-apps-script,firebase-realtime-database,google-sheets,Javascript,Json,Google Apps Script,Firebase Realtime Database,Google Sheets,提前感谢任何能够在这方面帮助我的人。几天来,我一直在努力使这项工作顺利进行,但我对这方面的了解还不够,无法通过示例来理解 我开发了一个Android应用程序,可以在实时数据库中下订单。每个订单都有自己的ID,该ID由应用程序生成。我希望在运行代码并根据列标题进入正确的列时,每个订单都显示在一行中。我发现这似乎完全符合我的需要(相同的JSON结构),但当我尝试重新调整用途时,它不起作用。以下是我所拥有的: function chunkArray(myArray, chunk_size){
function chunkArray(myArray, chunk_size){
var index = 0;
var arrayLength = myArray.length;
var tempArray = [];
for (index = 0; index < arrayLength; index += chunk_size) {
myChunk = myArray.slice(index, index+chunk_size);
// Do something if you want with the group
tempArray.push(myChunk);
}
return tempArray;
}
function flatten(arrayOfArrays){
return [].concat.apply([], arrayOfArrays);
}
function insertJSON(){
// this puts the keys in the correct place
var aOneName = "id";
var ss = SpreadsheetApp.getActiveSpreadsheet();
const sheet = ss.getSheetByName("orders");
var fileURL = "<-RT DB Link ->";
var res = UrlFetchApp.fetch(fileURL,{'muteHttpExceptions': true});
var content = res.getContentText();
var json = JSON.parse(content);
var rows = [Object.keys(json)]; // Retrieve entry column.
var toRows = rows[0].length;
var toRows = toRows + 1;
var rowsflate = flatten(rows);
var rowstocols = chunkArray(rowsflate, 1);
sheet.getRange("A2:A" + toRows).setValues(rowstocols); // sets column of IDs
sheet.getRange(1, 1).setValue(aOneName); // A1 name
var headers = json[rows[0][2]];
var getHeaders = [Object.keys(headers)];
sheet.getRange(1,2,getHeaders.length,getHeaders[0].length).setValues(getHeaders); // Put values to Spreadsheet.
content
var content = [];
var temp = [];
for (var i = 0; i < rows[0].length; i++) {
var temp2 = [Object.values(json[rows[0][i]])];// Retrieve values to be split.
Logger.log(temp2);
content.push(flatten(temp2));
}
var columncount1= rows[0].length;
var columncount2 = getHeaders[0].length;
sheet.getRange(2,2,columncount1,columncount2).setValues(content); // Put values to Spreadsheet.
}
再次重申,对此的任何指导都将不胜感激 我相信你的目标如下
- 您希望从
中检索值,并将解析后的值按json
标题“id”、“orderId”、“orderName”、“orderAddress”、“orderPhone”、“orderEmail”、“orderLatLong”、“orderDent”、“orderLend”、“orderTrain”、“orderDish”、“ordersan”、“orderTint”、“orderText”、“orderSign”、“orderTree”、“orderTotal”的顺序放入,“orderTotalCost”、“orderPaid”、“orderDelivered”
- 您希望使用谷歌应用程序脚本实现这一点
- 在JSON对象上,键的顺序是不能保证的。所以在您的例子中,我认为给出有序的头值是合适的
- 通过将头值声明为数组,我想提出以下流程。
- 声明标题值
- 创建用于放入电子表格的数组
- 将创建的数组放入电子表格
- 使用此脚本时,请启用V8运行时
预期:电子表格应该是什么样子的
,我无法理解检索您预期标题顺序的逻辑。我可以问一下您目标的细节吗?@Tanaike标题的目标是将其保持在“预期”的顺序“照片。运行脚本时,标题的顺序更改为字母顺序。总体目标是将每个JSON条目推送到正确标题下的每一行中。如果我解释得不好,我深表歉意。谢谢你的回复。从你的回复中,我提出了一个修改后的脚本作为答案。你能确认一下吗?如果我误解了你的目标,我道歉。@Tanaike谢谢你的帮助!对于代码const values=Object.entries(json.map)([k,v])=>{
:语法错误,我收到以下错误。(第167行,文件“code”)
。感谢您的回复。对于给您带来的不便,我深表歉意。从您的回复中,我担心您可能没有在脚本编辑器中启用V8运行时。如果是这样,请启用V8运行时并再次测试。如果我误解了您的情况,您能否提供复制您的问题的详细流程。我希望通过此确认。顺便说一句,根据你的问题,我建议使用样本值作为var JSON=JSON.parse(content);
的JSON
来编写脚本。我的理解正确吗?
{
"12":{
"orderAddress":"address 1",
"orderDelivered":"No",
"orderDent":2,
"orderDish":0,
"orderEmail":"Not Provided",
"orderId":"12",
"orderLatLong":"Not Captured",
"orderLend":1,
"orderName":"Name 1",
"orderPaid":"No",
"orderPhone":"Phone 1",
"orderSans":0,
"orderSign":8,
"orderText":6,
"orderTint":0,
"orderTotal":17,
"orderTotalCost":200,
"orderTrain":0,
"orderTree":0
},
"13":{
"orderAddress":"address 2",
"orderDelivered":"No",
"orderDent":0,
"orderDish":1,
"orderEmail":"Not Provided",
"orderId":"13",
"orderLatLong":"Not Captured",
"orderLend":1,
"orderName":"Name 2",
"orderPaid":"Yes",
"orderPhone":"Phone 2",
"orderSans":0,
"orderSign":0,
"orderText":0,
"orderTint":0,
"orderTotal":27,
"orderTotalCost":40,
"orderTrain":0,
"orderTree":0
},
"-MMIu9hQrxlZNs91nl2M":{
"orderAddress":"address 3",
"orderDelivered":"Yes",
"orderDent":0,
"orderDish":0,
"orderEmail":"Not Provided",
"orderId":"-MMIu9hQrxlZNs91nl2M",
"orderLatLong":"Not Captured",
"orderLend":1,
"orderName":"Name 3",
"orderPaid":"Yes",
"orderPhone":"Phone 3",
"orderSans":0,
"orderSign":0,
"orderText":0,
"orderTint":0,
"orderTotal":1,
"orderTotalCost":12,
"orderTrain":0,
"orderTree":0
}
}
var rows = [Object.keys(json)]; // Retrieve entry column.
var toRows = rows[0].length;
var toRows = toRows + 1;
var rowsflate = flatten(rows);
var rowstocols = chunkArray(rowsflate, 1);
sheet.getRange("A2:A" + toRows).setValues(rowstocols); // sets column of IDs
sheet.getRange(1, 1).setValue(aOneName); // A1 name
var headers = json[rows[0][2]];
var getHeaders = [Object.keys(headers)];
sheet.getRange(1,2,getHeaders.length,getHeaders[0].length).setValues(getHeaders); // Put values to Spreadsheet.
content
var content = [];
var temp = [];
for (var i = 0; i < rows[0].length; i++) {
var temp2 = [Object.values(json[rows[0][i]])];// Retrieve values to be split.
Logger.log(temp2);
content.push(flatten(temp2));
}
var columncount1= rows[0].length;
var columncount2 = getHeaders[0].length;
sheet.getRange(2,2,columncount1,columncount2).setValues(content); // Put values to Spreadsheet.
// 1. Declare the header values.
const header = ["id", "orderId", "orderName", "orderAddress", "orderPhone", "orderEmail", "orderLatLong", "orderDent", "orderLend", "orderTrain", "orderDish", "orderSans", "orderTint", "orderText", "orderSign", "orderTree", "orderTotal", "orderTotalCost", "orderPaid", "orderDelivered"];
// 2. Create an array for putting to Spreadsheet.
const values = Object.entries(json).map(([k, v]) => {
v.id = k;
return header.map(h => v[h]);
});
values.unshift(header); // When you want to add the header, please use this.
// 3. Put the created array to Spreadsheet.
sheet.getRange(1, 1, values.length, values[0].length).setValues(values);