模型提交后Javascript显示感谢模式

嗨，我有反馈表的模型。模型提交后应显示另一个感谢模型还需要存储本地存储。帮帮我

<div id="myModal2" class="modal fade" role="dialog">
<form action="" method="post" onSubmit="popUpToggle();" id="myModal2" >
<div class="form_fields feedbackfield">
<textarea id="txtMessage" name="txtMessage" rows="5" class="form-control contact-input" placeholder="Message *" required></textarea>
</div>
<div class="form_fields">
<input type="submit" class="contact-submit" name="SUBMIT" value="SUBMIT">
</div>
</form>
</div>

<div id="myModal4" class="modal fade" role="dialog">
      <div class="modal-dialog">                    
                <div class="popupHead3">
                   Thank you for your feedback    
                </div>    
      </div>

---

您可以尝试

AJAX

获取

form

submit

，然后使用

$('#myModal4').modal({show: 'true'});

请尝试下面的代码

$("#myModal2").submit(function(){
  event.stopPropagation();
  event.preventDefault();
  $.ajax({
    type: "POST",
    url: /* submit url or form action url */,
    data: $(this).serialize(),
    success: function(d){
      /* do here what you want to do */

      $("#myModal4").modal({show: "true"});
    },
    dataType: "JSON"
  });
});

---

我该怎么做。。？我把Popuptogle（）作为提交

$("#myModal2").submit(function(){
  event.stopPropagation();
  event.preventDefault();
  $.ajax({
    type: "POST",
    url: /* submit url or form action url */,
    data: $(this).serialize(),
    success: function(d){
      /* do here what you want to do */

      $("#myModal4").modal({show: "true"});
    },
    dataType: "JSON"
  });
});