Javascript 未捕获类型错误:child.dispatchEvent不是函数EaselJS
我正在尝试使用创建一个纸牌游戏。我在尝试将对象类添加到stage时出现了Javascript 未捕获类型错误:child.dispatchEvent不是函数EaselJS,javascript,jquery,debugging,createjs,easeljs,Javascript,Jquery,Debugging,Createjs,Easeljs,我正在尝试使用创建一个纸牌游戏。我在尝试将对象类添加到stage时出现了uncaughttypeerror:child.dispatchEvent不是函数EaselJS错误。我使用的是jQuery,但我遵循以下步骤删除jQuery冲突: <script src="lib/jQuery.js"></script> <script>jQuery.noConflict();</script> 卡类:我正在控制台上记录画布,以确保我没有丢
uncaughttypeerror:child.dispatchEvent不是函数EaselJS
错误。我使用的是jQuery
,但我遵循以下步骤删除jQuery冲突:
<script src="lib/jQuery.js"></script>
<script>jQuery.noConflict();</script>
卡类:我正在控制台上记录画布
,以确保我没有丢失上下文,并且它实际上记录了正确的Stage对象
var Card = function(canvas, args) {
var graphics = new createjs.Graphics();
graphics.beginStroke("red").beginFill("blue").drawRect(20, 20, 100, 50);
this.shape = new createjs.Shape(graphics);
this.set = new createjs.Container();
this.set.addChild(this.shape);
this.set.x = this.x;
this.set.y = this.y;
console.log('canvas', canvas); //outputs createJS Stage object
canvas.addChild(this); //Error seems to be because of this
我还尝试将卡添加到创建循环中:
for ...
for ...
var card = new Card(this.tableCanvas, card_data);
this.tableCanvas.addChild(card);
}
}
同样的错误
HTML代码片段:
this.tableCanvas = new createjs.Stage('Table');
function createDeck () {
for (var i = 0; i < suits.length; i++) {
for (var j = 0; j < values.length; j++) {
var card_data = { ... };
var card = new Card(this.tableCanvas, card_data);
...
}
}
this.tableCanvas.update();
<body>
<div id="GameBoard">
<canvas id="Table" width="1000" height="1000"></canvas>
</div>
</body>
错误:createjs-2015.11.26.combined.js:7322
p.addChild = function(child) {
if (child == null) { return child; }
var l = arguments.length;
if (l > 1) {
for (var i=0; i<l; i++) { this.addChild(arguments[i]); }
return arguments[l-1];
}
if (child.parent) { child.parent.removeChild(child); }
child.parent = this;
this.children.push(child);
child.dispatchEvent("added"); //ERROR HERE
return child;
};
p.addChild=function(child){
如果(child==null){return child;}
var l=arguments.length;
如果(l>1){
对于(var i=0;i我认为这是因为您正在将卡实例添加到stage。stage子项需要是DisplayObjects。您应该添加此项。改为将设置到画布中
我还要推荐你的第二种方法
this.tableCanvas.addChild(card.set);