如何使用Javascript遍历元素子节点?
我试图遍历DOM元素子元素,并在代码中显示它们的属性:如何使用Javascript遍历元素子节点?,javascript,html,Javascript,Html,我试图遍历DOM元素子元素,并在代码中显示它们的属性: document.write("<table border='1'>"); var testcaseiterator = xmlDoc.getElementsByTagName("TestCase")[1].childNodes; for(i=0; i < testcaseiterator.length; i++){ document.write("<tr><td>"); doc
document.write("<table border='1'>");
var testcaseiterator = xmlDoc.getElementsByTagName("TestCase")[1].childNodes;
for(i=0; i < testcaseiterator.length; i++){
document.write("<tr><td>");
document.write(testcaseiterator[i].getAttribute('name'));
document.write("</td></tr>");
}
document.write("</table>");
document.write(“”);
var testcaseiterator=xmlDoc.getElementsByTagName(“TestCase”)[1].childNodes;
对于(i=0;i
我的XML:
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="XSLTOutput2.xsl"?>
<TestSuite>
<ActiveStep case="6" step="14" />
<TestCase name="Visit all buttons [in region Button: Navi 0]">
<Verification type="screen" id="1e542f75-1ba2-482d-8edd-39f70620d6dd" status="">
<screen widgetid="audio_radio_fm">
<menu entryStrategy="FIRST" looped="false" orientation="HORIZONTAL" selectable="true" widgetid="status">
<entry selectable="true" widgetid="status" widgettype="entry">
<label widgetid="status_label">status</label>
</entry>
</menu>
<menu entryStrategy="SECOND" looped="false" orientation="HORIZONTAL" selectable="true" widgetid="apl">
<button selectable="true" widgetid="apl_navi" widgettype="button">
<label widgetid="apl_navi_label">Navi</label>
</button>
<button selectable="true" widgetid="apl_audio" widgettype="button">
<label widgetid="apl_audio_label">Audio</label>
</button>
<button selectable="true" widgetid="apl_tel" widgettype="button">
<label widgetid="apl_tel_label">Tel</label>
</button>
<button selectable="true" widgetid="apl_video" widgettype="button">
<label widgetid="apl_video_label">Video</label>
</button>
<button selectable="true" widgetid="apl_system" widgettype="button">
<label widgetid="apl_system_label">System</label>
</button>
<button selectable="true" widgetid="apl_net" widgettype="button">
<img src="img/apl_net.png" widgetid="apl_net_image" />
</button>
</menu>
<menu entryStrategy="FIRST" looped="false" orientation="HORIZONTAL" selectable="true" widgetid="plf">
<entry selectable="true" widgetid="playfield" widgettype="entry">
<label widgetid="playfield_label">playfield</label>
</entry>
</menu>
<menu entryStrategy="MIDDLE" looped="false" orientation="HORIZONTAL" selectable="true" widgetid="audio_radio_sfl">
<button selectable="true" widgetid="audio_radio_sfl_radio" widgettype="button">
<label widgetid="audio_radio_sfl_radio_label">Radio</label>
</button>
<button selectable="true" widgetid="audio_radio_sfl_presets" widgettype="button">
<label widgetid="audio_radio_sfl_presets_label">Presets</label>
</button>
<button selectable="true" widgetid="audio_radio_sfl_info" widgettype="button">
<label widgetid="audio_radio_sfl_info_label">Info</label>
</button>
<button selectable="true" widgetid="audio_radio_sfl_fm" widgettype="button">
<label widgetid="audio_radio_sfl_fm_label">FM</label>
</button>
<button selectable="true" widgetid="audio_radio_sfl_sound" widgettype="button">
<label widgetid="audio_radio_sfl_sound_label">Sound</label>
</button>
</menu>
</screen>
</Verification>
<Verification optionID="Audio" type="focus" id="d713b58b-06b1-4274-9a79-fe90a071383c" status="" />
<Command type="cce:left" id="3a591a3c-9b9f-41a7-9b50-0892197128ec" status="" />
<Verification optionID="Navi" type="focus" id="6037419a-25ae-4a7f-b842-0e88df9dfe4c" status="" />
</TestCase>
地位
纳维
音频
电话
视频
系统
操场
无线电
预设
信息
调频
声音
这不起作用:有什么想法吗
var testcaseiterator = xmlDoc.getElementsById("tc").childNodes;
代码的其余部分看起来没问题
for(i=0; i < testcaseiterator.length; i++)
{
document.write("<tr><td>");
document.write(testcaseiterator[i].getAttribute('name'));
document.write("</td></tr>");
}
document.write("</table>")
for(i=0;i
您还必须编辑XML的第5行
<TestCase id ="tc" name="Visit all buttons [in region Button: Navi 0]">
只有在DOM结构中使用XML时,这才有效。它怎么不起作用?发生了什么事?控制台上有错误吗?浏览器中没有错误。这张桌子就是不见了。如果我只是在document.write()中写一个字符串,那么它会用我的字符串打印几行。但数字不正确。您是否有
文档。是否在任何地方写入(“”
?子节点
对我不起作用,我使用了子节点
,效果很好。此子节点[i]。getAttribute('name')
对我不起作用,但它确实起作用:子节点[i]。标记名