用Javascript替换分隔字符串

我有一个字符串：

Mr Blue has a //start blue house and a blue //end car. 

我想用//start和//end替换带分隔符的字符串，因此字符串变成：

Mr Blue has a car.

我试过了

var res = str.replace(\//start(.*?)\//end, "");

---

它不起作用。

您可以使用此正则表达式：

\/\/start(.*?)\/\/end

Javascript代码

var re = /\/\/start(.*?)\/\/end/; 
var str = ' //start blue house and a blue //end';

var result = str.replace(re, '$1');

您可以使用以下选项：

var string = "Mr Blue has a //start blue house and a blue //end car. "
string = string.replace(/\/\/.*?\/\/\w+\s+/g, "");
alert(string)

输出： 演示： 正则表达式解释：

---

您可以使用这个正则表达式来匹配分隔符之间的任何字符，包括换行符\/\/start。|\n*\/\/end

我认为这在Javascript中都是无效的。试试/\/\/start.*？\/\/end/@LABLEBI：周围的空格呢？你需要只保留1个吗？是否会有//开始或//结束词？问题是/\/\/start.*.\/\/end/中的点匹配除新行以外的任何字符，我想匹配分隔符之间的任何内容，包括新行great，但是当我在字符串中执行换行操作时，reg不起任何作用more@LABLEBI您可以这样使用单行标志：？s\/\/start.*？\/\/end，也可以使用\/\/start[\s\s]*？\/\/end

Mr Blue has a car. 

//.*?//\w+\s+


Match the character string “//” literally «//»
Match any single character that is NOT a line break character «.*?»
   Between zero and unlimited times, as few times as possible, expanding as needed (lazy) «*?»
Match the character string “//” literally «//»
Match a single character that is a “word character” «\w+»
   Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Match a single character that is a “whitespace character” «\s+»
   Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»