Javascript 发现angularjs ng show ng的错误如果？

我发现angularjs有几个bug：

<div ng-show="['[]']">this should be show but actually not</div>
<div ng-show="[]">this should be show but actually not</div>
<div ng-show="[0]">this should be show but actually not</div>
<div ng-show="['0']">this should be show but actually not</div>

在javascript的if语句中使用这些条件时，它们被视为true。 但在ng show、ng hide、ng if中，它不能正常工作

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这是一个bug吗？

以上所有语句都是无效语句。我给你们举个例子

 //What you have done here  is created an array with a string of '[]' which has no expression to return true or false;
<div ng-show="['[]']">this should be show but actually not</div>

// Here is just an empty array again with no expression to return true or false. Better use would be myArray.length > 0 which will evaluate as true or false;
<div ng-show="[]">this should be show but actually not</div>

 //Here is just like the first one except you have an array of one number being 0 which will still never evaluate to a true or false;
<div ng-show="[0]">this should be show but actually not</div>

 //I dont think this one needs any explaining as you can see the pattern from above;
<div ng-show="['0']">this should be show but actually not</div>

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您未正确使用ng show/if。您总是需要一个可以计算true或false的表达式，或者一个将返回true或false的函数。不要将html中的角度表达式等同于javascript。

为什么要使用数组代替布尔值？空数组在角度表达式中的计算结果按设计为false。关于angularjs，请参见api文档，它只告诉truthy或falsy。我认为它只意味着正确或错误。