Javascript 将数组数据转换为对象
所以我有这个数组Javascript 将数组数据转换为对象,javascript,arrays,json,object,Javascript,Arrays,Json,Object,所以我有这个数组 ["2020-01-31 18:31:01", "2020-02-03 14:04:30", "2020-02-04 05:58:48", "2020-02-04 14:11:16"] 我喜欢把它转换成对象 0: {date: "2020-01-31", time: ["8:31:01"]} 1: {date: "2020-02-03", time: ["4:04:30"]} 2: {date: "2020-02-04", time: ["5:58:48", "14:11:1
["2020-01-31 18:31:01", "2020-02-03 14:04:30", "2020-02-04 05:58:48", "2020-02-04 14:11:16"]
我喜欢把它转换成对象
0: {date: "2020-01-31", time: ["8:31:01"]}
1: {date: "2020-02-03", time: ["4:04:30"]}
2: {date: "2020-02-04", time: ["5:58:48", "14:11:16"]}
但我得到了这个结果
0: {date: "2020-01-31", time: "8:31:01"}
1: {date: "2020-02-03", time: "4:04:30"}
2: {date: "2020-02-04", time: "5:58:48"}
这是我的密码
var times = response.data.time;
var dates = [];
var t = [];
var d = '';
var newData = [];
times.forEach(time => {
var da = time.substring(0, 10);
var ti = time.substring(12, 19);
if(d == da) {
t.push(ti);
} else {
d = da
var dt = {date: da, time: ti};
newData.push(dt);
}
});
我很难弄明白,希望你能帮我
谢谢。尝试使用以下功能:
const数组=[“2020-01-31 18:31:01”、“2020-02-03 14:04:30”、“2020-02-04 05:58:48”、“2020-02-04 14:11:16”];
const newData=array.reduce((acc,cur)=>{
常数[日期、时间]=当前拆分(“”);
const dateObj=acc.find(e=>e.date==date);
if(dateObj){
dateObj.time.push(时间);
}否则{
acc.push({日期,时间:[时间]});
}
返回acc;
}, []);
console.log(newData)
几乎是郝武解决方案的副本,但速度更快,因为它不依赖于线性查找。值被累积到一个对象中,允许快速查找,然后使用对象提取一个数组。值
:
const数组=[“2020-01-31 18:31:01”、“2020-02-03 14:04:30”、“2020-02-04 05:58:48”、“2020-02-04 14:11:16”];
const newData=Object.values(array.reduce)(acc,cur)=>{
常数[日期、时间]=当前拆分(“”);
如果(!acc[日期]){
acc[date]={日期,时间:[]};
}
acc[日期].时间.推送(时间);
返回acc;
}, {}));
console.log(newData)代码>