Javascript 子孙孙mysql查询

列视图

+-----------------------+
| name                  |
+-----------------------+
| ELECTRONICS           |
|  TELEVISIONS          |
|   TUBE                |
|   LCD                 |
|   PLASMA              |
|  GAME CONSOLES        |
|  PORTABLE ELECTRONICS |
|   MP3 PLAYERS         |
|    FLASH              |
|   CD PLAYERS          |
|   2 WAY RADIOS        |
|    FRS                |
+-----------------------+

表2.1.1类别

Id      ParentId   Name

1       null       ELECTRONICS
2       1          TELEVISIONS
3       2          TUBE
4       2          LCD
5       2          PLASMA
6       1          GAME CONSOLES
7       1          PORTABLE ELECTRONICS
8       7          MP3 PLAYERS
9       8          FLASH
10      7          CD PLAYERS
11      1          2 WAY RADIOS
12      11         FRS

如果我选择1

结果是（显示子女和孙子孙女）预期有超过1个祖父母（电子产品）

如果我选择2

结果必须是

+-----+
| id  |
+-----+
| 2   |
| 3   |
| 4   |
| 5   |
+-----+

我为选定的类别和他的孩子们得到了这个（需要更多来输出孙辈）

结果是

+-----+
| id  |
+-----+
| 1   |
| 2   |
| 6   |
| 7   |
| 11  |
+-----+

我应该在select语句中添加什么

WITH RECURSIVE categorytree AS (
  SELECT c.category_id, 0 as depth
  FROM core.category AS c
  WHERE c.category_id = $1::integer

  UNION ALL

  SELECT c.category_id, t.depth + 1 as depth
  FROM core.category AS c
  INNER JOIN categorytree t
    ON t.category_id = c.category_ParentId
)

SELECT category_id FROM categorytree

显示选定的和子孙辈等

+-----+
| id  |
+-----+
| 1   |
| 2   |
| 3   |
| 4   |
| 5   |
| 6   |
| 7   |
| 8   |
| 9   |
| 10  |
| 11  |
| 12  |
+-----+

---

这是在节点服务器中吗？如果不是，javascript和它有什么关系？除此之外：您是只想执行2个步骤还是完成所有步骤？（这意味着如果还有外祖父母，…）？我想显示所选类别下的所有内容，包括所选类别，这意味着您希望得到该类别及其下所有内容的递归结果（问题标题有点误导）。另外，正如前面提到的，您只使用mysql还是javascript（正如您在那里使用的标记一样）。如果是javascript：到目前为止，您有哪些代码，您使用哪些框架（如jquery、angularjs等）来编写javascript？这些都是重要的信息。您只想要

类别及其子类别

还是

类别及其子类别等等

WITH RECURSIVE categorytree AS (
  SELECT c.category_id, 0 as depth
  FROM core.category AS c
  WHERE c.category_id = $1::integer

  UNION ALL

  SELECT c.category_id, t.depth + 1 as depth
  FROM core.category AS c
  INNER JOIN categorytree t
    ON t.category_id = c.category_ParentId
)

SELECT category_id FROM categorytree

+-----+
| id  |
+-----+
| 1   |
| 2   |
| 3   |
| 4   |
| 5   |
| 6   |
| 7   |
| 8   |
| 9   |
| 10  |
| 11  |
| 12  |
+-----+