Javascript 这段代码可以重构成更短的代码吗？

我有以下代码

let objProvince = paramsData.find(element => element.name === "province")
      if (objProvince) {
        let error = false;
        if (objProvince.value === "VI" && value.substring(0, 2) !== "01") error = true
        if (objProvince.value === "AB" && value.substring(0, 2) !== "02") error = true
        if (objProvince.value === "A" && value.substring(0, 2) !== "03") error = true
        if (objProvince.value === "AL" && value.substring(0, 2) !== "04") error = true
        if (objProvince.value === "AV" && value.substring(0, 2) !== "05") error = true
        if (objProvince.value === "BA" && value.substring(0, 2) !== "06") error = true
        if (objProvince.value === "PM" && value.substring(0, 2) !== "07") error = true
        if (objProvince.value === "B" && value.substring(0, 2) !== "08") error = true
        if (objProvince.value === "BU" && value.substring(0, 2) !== "09") error = true
        if (objProvince.value === "CC" && value.substring(0, 2) !== "10") error = true
        if (objProvince.value === "CA" && value.substring(0, 2) !== "11") error = true
        if (objProvince.value === "CS" && value.substring(0, 2) !== "12") error = true
        if (objProvince.value === "CR" && value.substring(0, 2) !== "13") error = true
        if (objProvince.value === "CO" && value.substring(0, 2) !== "14") error = true
        if (objProvince.value === "C" && value.substring(0, 2) !== "15") error = true
        if (objProvince.value === "CU" && value.substring(0, 2) !== "16") error = true
        if (objProvince.value === "GI" && value.substring(0, 2) !== "17") error = true
        if (objProvince.value === "GR" && value.substring(0, 2) !== "18") error = true
        if (objProvince.value === "GU" && value.substring(0, 2) !== "19") error = true
        if (objProvince.value === "SS" && value.substring(0, 2) !== "20") error = true
        if (objProvince.value === "H" && value.substring(0, 2) !== "21") error = true
        if (objProvince.value === "HU" && value.substring(0, 2) !== "22") error = true
        if (objProvince.value === "J" && value.substring(0, 2) !== "23") error = true
        if (objProvince.value === "LE" && value.substring(0, 2) !== "24") error = true
        if (objProvince.value === "L" && value.substring(0, 2) !== "25") error = true
        if (objProvince.value === "LO" && value.substring(0, 2) !== "26") error = true
        if (objProvince.value === "LU" && value.substring(0, 2) !== "27") error = true
        if (objProvince.value === "M" && value.substring(0, 2) !== "28") error = true
        if (objProvince.value === "MA" && value.substring(0, 2) !== "29") error = true
        if (objProvince.value === "MU" && value.substring(0, 2) !== "30") error = true
        if (objProvince.value === "MA" && value.substring(0, 2) !== "31") error = true
        if (objProvince.value === "OR" && value.substring(0, 2) !== "32") error = true
        if (objProvince.value === "O" && value.substring(0, 2) !== "33") error = true
        if (objProvince.value === "P" && value.substring(0, 2) !== "34") error = true
        if (objProvince.value === "GC" && value.substring(0, 2) !== "35") error = true
        if (objProvince.value === "PO" && value.substring(0, 2) !== "36") error = true
        if (objProvince.value === "SA" && value.substring(0, 2) !== "37") error = true
        if (objProvince.value === "TF" && value.substring(0, 2) !== "38") error = true
        if (objProvince.value === "S" && value.substring(0, 2) !== "39") error = true
        if (objProvince.value === "SG" && value.substring(0, 2) !== "40") error = true
        if (objProvince.value === "SE" && value.substring(0, 2) !== "41") error = true
        if (objProvince.value === "SO" && value.substring(0, 2) !== "42") error = true
        if (objProvince.value === "T" && value.substring(0, 2) !== "43") error = true
        if (objProvince.value === "TE" && value.substring(0, 2) !== "44") error = true
        if (objProvince.value === "TO" && value.substring(0, 2) !== "45") error = true
        if (objProvince.value === "V" && value.substring(0, 2) !== "46") error = true
        if (objProvince.value === "VA" && value.substring(0, 2) !== "47") error = true
        if (objProvince.value === "BI" && value.substring(0, 2) !== "48") error = true
        if (objProvince.value === "ZA" && value.substring(0, 2) !== "49") error = true
        if (objProvince.value === "Z" && value.substring(0, 2) !== "50") error = true
        if (objProvince.value === "CE" && value.substring(0, 2) !== "51") error = true
        if (objProvince.value === "ML" && value.substring(0, 2) !== "52") error = true

        if (error) {............

看起来很大，但我不确定我怎么能缩短这个

我在考虑做一些事情，比如：

const provinces = ["VI" , "AB", "A", "AL", "AV", "BA", "PM" , "B" ,"BU", "CC", "CA", "CS", "CR", "CO", "C", "CU", "GI", "GR", "GU", "SS", "H", 
"HU", "J","LE","L","LO","LU","M","MA","MU","MA","OR","O","P","GC","PO","SA","TF","S","SG","SE","SO","T","TE","TO","V","VA","BI","ZA","Z","CE","ML"]


function proviceCheck (_provinceValue) {
    let indexPosition = array.indexOf(_provinceValue) + 1;
    let formatedIndex = ""
    
    if(indexPosition < 10){
        formatedIndex = ('0'+indexPosition).slice(-2);
    }else{
        formatedIndex = indexPosition.toString()
    }
    
    if(provinces.includes(_provinceValue) && provinceValue.substring(0,2) !== formatedIndex return true;
    
    return false;
} 

if(objProvince){
    let error = false;
    error = provinceCheck(objProvince.value)
    
    if(error) {......
}

const省=[“VI”、“AB”、“A”、“AL”、“AV”、“BA”、“PM”、“B”、“BU”、“CC”、“CA”、“CS”、“CR”、“CO”、“C”、“CU”、“GI”、“GR”、“GU”、“SS”、“H”，
“HU”、“J”、“LE”、“L”、“LO”、“LU”、“M”、“MA”、“MU”、“MA”、“OR”、“O”、“P”、“GC”、“PO”、“SA”、“TF”、“S”、“SG”、“SE”、“SO”、“T”、“TE”、“TO”、“V”、“VA”、“BI”、“ZA”、“Z”、“CE”、“ML”]
函数providecheck（\u providecvalue）{
设indexPosition=array.indexOf（_provinceValue）+1；
让FormattedIndex=“”
如果（扩展位置<10）{
FormattedIndex=（'0'+索引展开）.slice（-2）；
}否则{
formatedIndex=indexPosition.toString（）
}
if（省包括（_provinceValue）&&provinceValue.substring（0,2）！==formattedIndex返回true；
返回false；
} 
如果（OBJ省）{
让错误=错误；
错误=provinceCheck（objProvince.value）
如果（错误）{。。。。。。
}

问题是数组28和30的索引是重复的，所以我不能使用我的

indexOf

思想

有没有其他的方法来重构它？也许是用一些函数代码。但是我不知道其他的解决方案

---

请注意，我上面的解决方案被破坏了，因为数组有一个重复的索引值28==30，我想反过来-提取索引，然后检查

\u provinceValue

是否匹配它：

function proviceCheck (_provinceValue) {
    const index = Number(provinceValue.substring(0,2)) - 1;

    return provinces[index] === _provinceValue;
} 

---

我会反过来-提取索引，然后检查

\u provinceValue

是否匹配它：

function proviceCheck (_provinceValue) {
    const index = Number(provinceValue.substring(0,2)) - 1;

    return provinces[index] === _provinceValue;
} 

---

为了避免索引错误，您可以通过在“省”数组中的所有省上循环，在所有省名称旁边生成一个数字，我会这样做：

const provinces = ["VI" , "AB", "A", "AL", "AV", "BA", "PM"].map((a, b) => {'name': a, 'index': b}]);

现在您可以执行

省[index].name

来获取名称，并

省[index].index

---

要获取其索引

可以避免索引错误的方法是通过在省数组中的所有省上循环，在所有省名称旁边生成一个数字，我将这样做：

const provinces = ["VI" , "AB", "A", "AL", "AV", "BA", "PM"].map((a, b) => {'name': a, 'index': b}]);

现在您可以执行

省[index].name

来获取名称，并

省[index].index

---

要获取其索引

，可以使用字典简化逻辑，并使用该字典验证返回的对象值是否为已知键，以及其值是否正确

const provinces = {
  "VI": "01",
  "AB": "02",
  "A": "03",
  "AL": "04",
  "AV": "05",
  "BA": "06",
  "PM": "07",
  "B": "08",
  "BU": "09",
  "CC": "10",
  "CA": "11",
  // the rest ...
};

objProvince = paramsData.find(element => element.name === "province");
let error = false;
if (objProvince && provinces.hasOwnProperty(objProvince.value))
  error = value.substring(0, 2) !== provinces[objProvince.value];

---

您可以通过使用字典来简化逻辑，并使用这样的字典来验证返回的对象值是已知的键，并且其值是正确的

const provinces = {
  "VI": "01",
  "AB": "02",
  "A": "03",
  "AL": "04",
  "AV": "05",
  "BA": "06",
  "PM": "07",
  "B": "08",
  "BU": "09",
  "CC": "10",
  "CA": "11",
  // the rest ...
};

objProvince = paramsData.find(element => element.name === "province");
let error = false;
if (objProvince && provinces.hasOwnProperty(objProvince.value))
  error = value.substring(0, 2) !== provinces[objProvince.value];

---

你能解释一下“索引值28==30”是什么意思吗？因为只有一个问题，你可以先从它开始。这对你有用吗？如果你希望更多，你可以使用一个数据结构，其中provinceValue与一系列错误的值相关联。@phtrivier如果你检查数组，索引28是“MA”，指数30是“MA”，你能解释一下“指数值28==30”是什么意思吗？由于只有一个问题，您可以先进行分支。这对您有用吗？如果您希望得到更多，可以使用一个数据结构，其中provinceValue与错误值列表相关联。@phtrivier如果您检查数组，索引28是“MA”，索引30也是“MA”