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Javascript 仅脚本首先更改<;p>;要素_Javascript_Html_Getelementsbytagname - Fatal编程技术网

Javascript 仅脚本首先更改<;p>;要素

Javascript 仅脚本首先更改<;p>;要素,javascript,html,getelementsbytagname,Javascript,Html,Getelementsbytagname,下面是我的页面的javascript: window.onmouseover = function(){ var body = document.getElementsByTagName("body") var h1 = document.getElementsByTagName("h1"); var a = document.getElementsByTagName("a"); var p = document.getEl

下面是我的页面的javascript:

    window.onmouseover = function(){
        var body = document.getElementsByTagName("body")
        var h1 = document.getElementsByTagName("h1");
        var a = document.getElementsByTagName("a");
        var p = document.getElementsByTagName("p")
        for(var j = 0; j < p.length; j++) {
            body[j].style.fontFamily = "helvetica";
            body[j].style.backgroundColor = "rgb(250, 250, 240)"
            p[j].style.fontFamily = "courier";
            a[j].onclick = function() {
                this.style.backgroundColor = "Black"
            }
        }
    }
window.onmouseover=function(){
var body=document.getElementsByTagName(“body”)
var h1=document.getElementsByTagName(“h1”);
var a=document.getElementsByTagName(“a”);
var p=document.getElementsByTagName(“p”)
对于(var j=0;j

我有一个h1元素,一个a元素和10个p元素。出于某种原因,这段代码只更改第一个p元素的字体,尽管其他一切都可以正常工作?这是为什么?我如何修复它?

它可能会在循环中第二次生成错误,因为
body[1]
将无效。移动对象,以便循环中只有
p
上的操作。

如果只有一个
a
元素,并且(当然)只有一个
body
,则不能对其中的10个进行迭代。这会在循环的第二次迭代中导致错误。请改用此代码

window.onmouseover = function(){
    var body = document.getElementsByTagName("body")
    var h1 = document.getElementsByTagName("h1");
    var a = document.getElementsByTagName("a");
    var p = document.getElementsByTagName("p")

    body[0].style.fontFamily = "helvetica";
    body[0].style.backgroundColor = "rgb(250, 250, 240)"
    a[0].onclick = function() {
        this.style.backgroundColor = "Black"
    }

    for (var j = 0; j < p.length; j++) {
        p[j].style.fontFamily = "courier";
    }
}
window.onmouseover=function(){
var body=document.getElementsByTagName(“body”)
var h1=document.getElementsByTagName(“h1”);
var a=document.getElementsByTagName(“a”);
var p=document.getElementsByTagName(“p”)
正文[0]。style.fontfamic=“helvetica”;
正文[0]。style.backgroundColor=“rgb(250250240)”
a[0]。onclick=function(){
this.style.backgroundColor=“黑色”
}
对于(var j=0;j