Javascript 弹出框错误

当我单击弹出消息上的“取消”时，它仍然会删除记录，我不知道为什么

<tr>
    <td class="recordCells">
        <div align="center">
            <a onclick="confirm('Are you sure you want to delete this record?')" href="deleterecord.php?ID=<?php echo $row_rsInventory['ID']; ?>">
                <img src="../images/x.png" align="absmiddle">
            </a>
        </div>
    </td>
</tr>

---

您不会返回确认框的值：

<tr>
    <td class="recordCells">
        <div align="center">
            <a onclick="return(confirm('Are you sure you want to delete this record?'))" href="deleterecord.php?ID=<?php echo $row_rsInventory['ID']; ?>">
                <img src="../images/x.png" align="absmiddle">
            </a>
        </div>
    </td>
</tr>

---

实际上，锚点标记中存在“href=deleterecord.php文件”问题，因此您可以使用类似这样的代码：

jQuery(".confirm_click").click(function(){
    var check = confirm("Are you sure you want to delete this record?");
    if(check == true){
      // Action - Record deleted
      var url= jQuery(this).attr("url");
      jQuery(location).attr('href',url);      
    }else{
      // Action - none
    }
  });

Html代码：-

        <a class="confirm_click" href="" url="deleterecord.php?ID=<?php echo $row_rsInventory['ID']; ?>">
            <img src="../images/x.png" align="absmiddle">
        </a>

或者你可以给我发一部分“莫希特”的代码。tiwari@techinfini.com“我会用适当的方式来做的