Matlab interp2外推
我正在使用Matlab interp2外推,matlab,extrapolation,Matlab,Extrapolation,我正在使用interp2进行二维插值。对于某些数据值 interp2命令返回NaN,因为其中一个维度在外部 由已知值的向量定义的范围 可以使用interp1命令进行推断。然而,它是 对于interp2,有没有办法做到这一点 谢谢 以下是我使用interp2命令的代码: function [Cla] = AirfoilLiftCurveSlope(obj,AFdata,Rc,M) % Input: % AFdata: Airfoil coordinates. % Rc: Local Reynol
interp2
进行二维插值。对于某些数据值
interp2命令返回NaN,因为其中一个维度在外部
由已知值的向量定义的范围
可以使用interp1
命令进行推断。然而,它是
对于interp2
,有没有办法做到这一点
谢谢
以下是我使用interp2命令的代码:
function [Cla] = AirfoilLiftCurveSlope(obj,AFdata,Rc,M)
% Input:
% AFdata: Airfoil coordinates.
% Rc: Local Reynolds number.
% M: Mach number for Prandtle Glauert compressibility correction.
% Output:
% Cla: 2 dimensional lift curve slopea applicable to linear region of lift polar.
load('ESDU84026a.mat');
xi = size(AFdata);
if mod(xi(1,1),2) == 0
%number is even
AFupper = flipud(AFdata(1:(xi(1,1)/2),:));
AFlower = AFdata(((xi(1,1)/2)+1):end,:);
else
%number is odd
AFupper = flipud(AFdata(1:floor((xi(1,1)/2)),:));
AFlower = AFdata((floor(xi(1,1)/2)+1):end,:);
end
t_c = Airfoil.calculateThickness(AFdata(:,2));
Y90 = ((interp1(AFupper(:,1),AFupper(:,2),0.9,'linear')) - (interp1(AFlower(:,1),AFlower(:,2),0.9,'linear')))*100;
Y99 = ((interp1(AFupper(:,1),AFupper(:,2),0.99,'linear')) - (interp1(AFlower(:,1),AFlower(:,2),0.99,'linear')))*100;
Phi_TE = (2 * atan( ( (Y90/2) - (Y99/2) )/9))*180/pi; % Degrees
Tan_Phi_Te = ( (Y90/2) - (Y99/2) )/9;
Cla_corr = interp2(Tan_Phi,Rc_cla,cla_ratio,Tan_Phi_Te,Rc,'linear');
beta =sqrt((1-M^2)); % Prandtle Glauert correction
Cla_theory = 2*pi + 4.7*t_c*(1+0.00375 * Phi_TE); % per rad
Cla = (1.05/beta) * Cla_corr * Cla_theory; % per rad
if isnan(Cla) == 1 %|| Cla > 2*pi
Cla = 2*pi;
end
end
是的,有两种方法可以获取
interp2
,以根据返回有意义的越界值
“样条曲线”
插值方法。与选项#2不同,这实际上将根据样条曲线的边界条件推断数据extrapval
参数。对于所有其他插值方法,将返回该常数,而不是NaN
x = [x(1, 1), x(1, :), x(1, end); ...
x(:, 1), x, x(:, end); ...
x(end, 1), x(end, :), x(end, end)]
是的,有两种方法可以获取
interp2
,以根据返回有意义的越界值
“样条曲线”
插值方法。与选项#2不同,这实际上将根据样条曲线的边界条件推断数据extrapval
参数。对于所有其他插值方法,将返回该常数,而不是NaN
x = [x(1, 1), x(1, :), x(1, end); ...
x(:, 1), x, x(:, end); ...
x(end, 1), x(end, :), x(end, end)]
嘿,请找到我的interp2代码,它只需要最大值
function vq = Linear2dInterpWithClipExtrap(x,y,v,xq,yq);
vq = interp2(x,y,v,xq,yq);
[XMax, idxVMax] = max(x);
[XMin, idxVMin] = min(x);
idxMax = xq > XMax;
idxMin = xq < XMin;
if ~isempty(yq(idxMax));
vq(idxMax) = LinearInterpWithClipExtrap(y,v(:,idxVMax),yq(idxMax));
end
if ~ isempty(yq(idxMin))
vq(idxMin) = LinearInterpWithClipExtrap(y,v(:,idxVMin),yq(idxMin));
end
[YMax, idyVMax] = max(y);
[YMin, idyVMin] = min(y);
idyMax = yq > YMax;
idyMin = yq < YMin;
if ~isempty(xq(idyMax));
vq(idyMax) = LinearInterpWithClipExtrap(x,v(idyVMax,:),xq(idyMax));
end
if ~ isempty(xq(idyMin));
vq(idyMin) = LinearInterpWithClipExtrap(x,v(idyVMin,:),xq(idyMin));
end
function vq = LinearInterpWithClipExtrap(x,v,xq);
vq = interp1(x,v,xq);
[XMax, idxVMax] = max(x);
[XMin, idxVMin] = min(x);
idxMax = xq > XMax;
idxMin = xq < XMin;
vq(idxMax) = v(idxVMax);
vq(idxMin) = v(idxVMin
函数vq=Linear2dInterpWithClipExtrap(x,y,v,xq,yq);
vq=interp2(x,y,v,xq,yq);
[XMax,idxVMax]=max(x);
[XMin,idxVMin]=min(x);
idxMax=xq>XMax;
idxMin=xqYMax;
idyMin=yqXMax;
idxMin=xq
)) 嘿,请找到我的interp2代码,它只取最大界限值
function vq = Linear2dInterpWithClipExtrap(x,y,v,xq,yq);
vq = interp2(x,y,v,xq,yq);
[XMax, idxVMax] = max(x);
[XMin, idxVMin] = min(x);
idxMax = xq > XMax;
idxMin = xq < XMin;
if ~isempty(yq(idxMax));
vq(idxMax) = LinearInterpWithClipExtrap(y,v(:,idxVMax),yq(idxMax));
end
if ~ isempty(yq(idxMin))
vq(idxMin) = LinearInterpWithClipExtrap(y,v(:,idxVMin),yq(idxMin));
end
[YMax, idyVMax] = max(y);
[YMin, idyVMin] = min(y);
idyMax = yq > YMax;
idyMin = yq < YMin;
if ~isempty(xq(idyMax));
vq(idyMax) = LinearInterpWithClipExtrap(x,v(idyVMax,:),xq(idyMax));
end
if ~ isempty(xq(idyMin));
vq(idyMin) = LinearInterpWithClipExtrap(x,v(idyVMin,:),xq(idyMin));
end
function vq = LinearInterpWithClipExtrap(x,v,xq);
vq = interp1(x,v,xq);
[XMax, idxVMax] = max(x);
[XMin, idxVMin] = min(x);
idxMax = xq > XMax;
idxMin = xq < XMin;
vq(idxMax) = v(idxVMax);
vq(idxMin) = v(idxVMin
函数vq=Linear2dInterpWithClipExtrap(x,y,v,xq,yq);
vq=interp2(x,y,v,xq,yq);
[XMax,idxVMax]=max(x);
[XMin,idxVMin]=min(x);
idxMax=xq>XMax;
idxMin=xqYMax;
idyMin=yqXMax;
idxMin=xq
)) 请你详细说明你的第一点好吗?我似乎不明白你想用它说什么。感谢you@BalrajBoyal. 我不知道有什么不清楚,但我认为新的措辞会澄清问题。你能详细说明你的第一点吗?我似乎不明白你想用它说什么。感谢you@BalrajBoyal. 我不知道有什么不清楚,但我认为新的措辞会把它弄清楚。