Php 如何通过使用auth和body raw从狂饮中获得响应？

我试着在邮递员身上这样做：

public function testApi()
{
    $requestContent = [
        'headers' => [
            'Accept' => 'application/json',
            'Content-Type' => 'application/json'
        ],
        'json' => [
            'auth' => ['', 'b0a619c152031d6ec735dabd2c6a7bf3f5faaedd'],
            'ids' => ["1"]
        ]
    ];
    try {
        $client = new GuzzleHttpClient();
        $apiRequest = $client->request('POST', 'https://myshop/api/order', $requestContent);
        $response = json_decode($apiRequest->getBody());
        dd($response);
    } catch (RequestException $re) {
          // For handling exception.
    }
}

我只需输入密码。然后我点击按钮更新请求

这样的观点：

public function testApi()
{
    $requestContent = [
        'headers' => [
            'Accept' => 'application/json',
            'Content-Type' => 'application/json'
        ],
        'json' => [
            'auth' => ['', 'b0a619c152031d6ec735dabd2c6a7bf3f5faaedd'],
            'ids' => ["1"]
        ]
    ];
    try {
        $client = new GuzzleHttpClient();
        $apiRequest = $client->request('POST', 'https://myshop/api/order', $requestContent);
        $response = json_decode($apiRequest->getBody());
        dd($response);
    } catch (RequestException $re) {
          // For handling exception.
    }
}

这是标题：

这是尸体。我选择原始数据和输入数据，如下所示：

public function testApi()
{
    $requestContent = [
        'headers' => [
            'Accept' => 'application/json',
            'Content-Type' => 'application/json'
        ],
        'json' => [
            'auth' => ['', 'b0a619c152031d6ec735dabd2c6a7bf3f5faaedd'],
            'ids' => ["1"]
        ]
    ];
    try {
        $client = new GuzzleHttpClient();
        $apiRequest = $client->request('POST', 'https://myshop/api/order', $requestContent);
        $response = json_decode($apiRequest->getBody());
        dd($response);
    } catch (RequestException $re) {
          // For handling exception.
    }
}

然后我点击发送按钮，它可以得到响应

但是当我试着像这样使用guzzle 6时：

public function testApi()
{
    $requestContent = [
        'headers' => [
            'Accept' => 'application/json',
            'Content-Type' => 'application/json'
        ],
        'json' => [
            'auth' => ['', 'b0a619c152031d6ec735dabd2c6a7bf3f5faaedd'],
            'ids' => ["1"]
        ]
    ];
    try {
        $client = new GuzzleHttpClient();
        $apiRequest = $client->request('POST', 'https://myshop/api/order', $requestContent);
        $response = json_decode($apiRequest->getBody());
        dd($response);
    } catch (RequestException $re) {
          // For handling exception.
    }
}

结果是空的

---

如何解决此问题？

请参见《邮递员》中的内容，您在“邮件头”选项卡中正确指定了

授权

。所以当你使用Guzzle时应该是一样的，把它放在标题中：

public function testApi()
{
    $requestContent = [
        'auth' => ['username', 'password']
        'headers' => [
            'Accept' => 'application/json',
            'Content-Type' => 'application/json',
        ],
        'json' => [
            'ids' => ["1"]
        ]
    ];

    try {
        $client = new GuzzleHttpClient;
        $apiRequest = $client->request('POST', 'https://myshop/api/order', $requestContent);
        $response = json_decode($apiRequest->getBody());
        dd($response);
    } catch (RequestException $re) {
          // For handling exception.
    }
}

---

看来我的服务器有问题了。所以我不能尝试。后来我试了一下，效果很好。我会接受你的回答好的，让我知道。我编辑了我的答案，因为我忘记了

'Content-Type'=>'application/json'

行末尾的逗号。我试过了。但它不起作用。它重定向到页面登录。这似乎不太可信。我看到在你的编码中，没有身份验证。但在我展示的邮递员中，它似乎是这样的：

“授权”=>“基本b0a619c152031d6ec735dabd2c6a7bf3f5faaedd”

<代码>b0a619c152031d6ec735dabd2c6a7bf3f5faaedd并且输入了密码，它不应该是我输入的相同密码：

2AE694A084650944EA04AB21506E8E740FB55B6EB

当我在邮递员上单击更新请求时，标题中的结果是：

基本OJHZTY5NGEWODQ2NTA55NGVHMDRHYXNTA2ZLHLNZMI1NWI2WI=/code>