Php SQL:Can’；t使用group by时，按降序获取值

我使用下面的查询连接并检索两个表中的值。它按降序显示值

Leads
63697       Ben
63698       Ben
63699       Ben
63700       Ben
63701       Ben


log

2   63697       Ben         10%     Qualifying
3   63697       Ben         20%     Qualifying
4   63697       Ben         30%     Qualifying
6   63698       Ben         30%     Qualifying
8   63698       Ben     80%     Quoted
10  63698       Ben         70%     Quoted

我想展示一下

63697       Ben         30%     Qualifying
63698       Ben         70%     Quoted
63699       Ben
63700       Ben
63701       Ben

问题是当我使用查询时

SELECT leads.id,leads.name, log.prob, log.current_stage FROM leads LEFT JOIN log ON log.leadid = leads.id WHERE leads.name = '$name' ORDER BY log.id DESC

它按降序显示日志表的所有详细信息。但当我试着把他们分组时

SELECT leads.id,leads.name, log.prob, log.current_stage FROM leads LEFT JOIN log ON log.leadid = leads.id WHERE leads.name = '$name' GROUP BY log.leadid ORDER BY log.id DESC

它从logs表中按升序获取值

63697       Ben         10%     Qualifying
63698       Ben         30%     Qualifying
63699       Ben
63700       Ben
63701       Ben

有人能告诉我我做错了什么吗

SELECT * FROM (
SELECT leads.id,leads.name, log.prob, log.current_stage, log.id AS logid FROM leads LEFT JOIN log ON log.leadid = leads.id WHERE leads.name = '$name' GROUP BY log.leadid
) ORDER BY logid DESC

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我们经常看到这一点，只需将其包装在superquery中，如图所示。

您是按log.id排序的，它不是您选择的字段。无法执行此操作，因为ORDER BY是在SELECT指令之后计算的

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将ORDER BY log.id更改为ORDER BY leads.id，这是我在SELECT指令中看到的唯一标识符。

非常感谢。。。。但我必须将组移动到包装外，并在子查询内按顺序移动，以使其工作…：）