Php 通过在奇数/偶数数字键上拆分数组,我做错了什么?
我无法将数组一分为二Php 通过在奇数/偶数数字键上拆分数组,我做错了什么?,php,arrays,split,Php,Arrays,Split,我无法将数组一分为二 Array ( [0] => livree [1] => 2011-12-26 [2] => livree [3] => 2011-12-27 [4] => livree [5] => 2011-12-28 [6] => livree [7] => 2011-12-29 [8] => livree [9] => 2011-12-30
Array
(
[0] => livree
[1] => 2011-12-26
[2] => livree
[3] => 2011-12-27
[4] => livree
[5] => 2011-12-28
[6] => livree
[7] => 2011-12-29
[8] => livree
[9] => 2011-12-30
[10] => livree
[11] => 2011-12-31
[12] => livree
[13] => 2012-01-01
[14] => livree
[15] => 2012-01-02
[16] => livree
[17] => 2012-01-03
[18] => en_cours
[19] => 2012-01-04
[20] => en_cours
[21] => 2012-01-05
[22] => en_cours
[23] => 2012-01-06
[24] => en_cours
[25] => 2012-01-07
[26] => en_cours
[27] => 2012-01-08
)
我使用这些函数检测奇偶键,并将其拆分为两个不同的数组:
function odd($var){return($var & 1);}
function even($var){return(!($var & 1));}
$odd = array_filter($vb, "odd");
$even = array_filter($vb, "even");
我只有两个数组:
Array
(
[0] => 2011-12-26
[1] => 2011-12-27
[2] => 2011-12-28
[3] => 2011-12-29
[4] => 2011-12-30
[5] => 2011-12-31
[6] => 2012-01-01
[7] => livree
[8] => livree
[9] => en_cours
[10] => en_cours
[11] => en_cours
[12] => en_cours
[13] => en_cours
)
Array
(
[0] => livree
[1] => livree
[2] => livree
[3] => livree
[4] => livree
[5] => livree
[6] => livree
[7] => 2012-01-02
[8] => 2012-01-03
[9] => 2012-01-04
[10] => 2012-01-05
[11] => 2012-01-06
[12] => 2012-01-07
[13] => 2012-01-08
)
我做错了什么???谢谢你的帮助 for($i=0;$ifunction is_odd($num)
{
if ($num % 2 == 0)
return false;
else
return true;
}
$even_array=array();
$odd_rray=array();
foreach($array as $key=>$val)
{
if(is_odd($key))
array_push($odd_array,$val)
else
array_push($even_array,$val)
}
print_r($even_array);
print_r($odd_array);
$偶数[]=$yourarray[$i];
$odd[]=$yourarray[$i+1];
}
//查看数组是否有偶数个元素,例如,如果它将有28个元素而不是27个元素,那么我们将错过循环中的第28个元素。所以我们必须检查它并将其添加到偶数数组中。
如果((sizeof($yourarray)%2)==0)
$偶数[]=$yourarray[sizeof($yourarray-1)];
就这样 我不擅长PHP,但以下是我在C#中要做的事情(不使用LINQ):
有一些PHP实现,例如在。
array\u filter
向您传递值,而不是键。我无法理解为什么您会得到这些结果,但无论如何,您根本不需要阵列过滤器:
更快的方法:
$odd = $even = array();
for ($i = 0, $l = count($vb); $i < $l;) { // Notice how we increment $i each time we use it below, by two in total
$even[] = $vb[$i++];
$odd[] = $vb[$i++];
}
foreach (array_chunk($vb, 2) as $chunk) {
$even[] = $chunk[0];
$odd[] = $chunk[1];
}
…出于某种原因,我还认为您确实需要关联数组:
foreach (array_chunk($vb, 2) as $chunk) {
$days[$chunk[1]] = $chunk[0];
}
作用于值,而不是键。您需要尝试其他方法,请查看并检查以下内容:您的示例数组和代码没有生成您显示的两个数组。您,我的朋友,rock!非常感谢。很好,谢谢你的帮助。我保留@sad_dude解决方案。再一次,谢谢你
object[] stringValues = input.Where((obj, index) => index % 2 == 0).ToArray();
object[] dateValues = input.Where((obj, index) => index % 2 == 1).ToArray();
$odd = $even = array();
for ($i = 0, $l = count($vb); $i < $l;) { // Notice how we increment $i each time we use it below, by two in total
$even[] = $vb[$i++];
$odd[] = $vb[$i++];
}
foreach (array_chunk($vb, 2) as $chunk) {
$even[] = $chunk[0];
$odd[] = $chunk[1];
}
foreach (array_chunk($vb, 2) as $chunk) {
$days[$chunk[1]] = $chunk[0];
}