Php 将查询与PDO准备语句中的if-else连接起来

我试图将简单的MySQLi查询转换为PDO准备的语句 这是旧代码

if($mode=='')
{
    $query="SELECT * FROM items WHERE 1";
    if($CuisineId != '')
    {
        $query=$query. " AND CuisineId='$CuisineId' ";
    }
    if($CategoryId != '')
    {
        $query=$query. " AND CategoryId='$CategoryId'  ";
    }
    if($DietId != '')
    {
        $query=$query. " AND DietId='$DietId' ";
    }

    $query=$query. " ORDER BY Name ";

    $result= execute_query($con,$query) or die(mysqli_error($con));
    echo "<option value=''>Select One</option>";
    while ($row=mysqli_fetch_array($result)) {
        echo "<option value=". $row['Id'] .">" . $row['Name'] . "</option>";
    }
}

如果我开始做If-ELSE将所有的可能性，它将使我的代码太长。有没有办法解决这个问题

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提前感谢：）

您不需要连接此查询

SELECT * 
FROM items 
WHERE (? is null or CuisineId = ?)
  and (? is null or CategoryId = ?)
  and (? is null or DietId = ?)
ORDER BY Name

$stmt->execute(array($CuisineId,$CategoryId,$DietId));

SELECT * 
FROM items 
WHERE (? is null or CuisineId = ?)
  and (? is null or CategoryId = ?)
  and (? is null or DietId = ?)
ORDER BY Name