Php 如何从url获取图像的名称？

我有一个小问题；在PHP中，我使用curl从URL获取数据：

$url = "http://www.prelovac.com/vladimir/wp-content/uploads/2008/03/example.jpg";

我使用了

curl\u getinfo（）

，它给了我一个数组：

Array
(
[url] => http://www.prelovac.com/vladimir/wp-content/uploads/2008/03/example.jpg
[content_type] => image/jpeg
[http_code] => 200
[header_size] => 496
[request_size] => 300
[filetime] => -1
[ssl_verify_result] => 0
[redirect_count] => 0
[total_time] => 2.735
[namelookup_time] => 0.063
[connect_time] => 0.063
[pretransfer_time] => 0.063
[size_upload] => 0
[size_download] => 34739
[speed_download] => 12701
[speed_upload] => 0
[download_content_length] => 34739
[upload_content_length] => -1
[starttransfer_time] => 1.282
[redirect_time] => 0
)

如何在链接

[url]=>http://www.prelovac.com/vladimir/wp-content/uploads/2008/03/example.jpg

例如

[image_name] : example
[image_ex] : jpg

---

谢谢你的建议

使用

考虑以下是图像路径 $image_url=''； 使用以下函数basename（）从该url获取扩展名为的图像名称； 看看下面的代码

代码：

输出：

---

attorney1.png

有时url会附加额外的参数。在这种情况下，我们可以先删除参数部分，然后使用PHP内置的pathinfo（）函数从url获取图像名称

$url = 'http://images.fitnessmagazine.mdpcdn.com/sites/story/shutterstock_65560759.jpg?itok=b8HiA95H';

检查图像url是否附加了参数

if (strpos($url, '?') !== false) {
    $t = explode('?',$url);
    $url = $t[0];            
}      

结果url变量现在包含

http://images.fitnessmagazine.mdpcdn.com/sites/story/shutterstock_65560759.jpg

使用以检索所需的详细信息

$pathinfo = pathinfo($url);
echo $pathinfo['filename'].'.'.$pathinfo['extension'];

这将提供shutterstock_65560759.jpg作为输出。

您可以使用正则表达式

/（？：.+\/）（.+\.（png | jpg | jepg））[？#].$/

例如：

$examples=[
'http://images.fitnessmagazine.mdpcdn.com/sites/story/with_query.jpg?itok=b8HiA95H',
'http://images.fitnessmagazine.mdpcdn.com/sites/story/with_hash.jpg#hghgh',
'http://images.fitnessmagazine.mdpcdn.com/sites/story/with_query.jpg?',
'http://images.fitnessmagazine.mdpcdn.com/sites/story/with_hash.jpg#',
'http://images.fitnessmagazine.mdpcdn.com/sites/story/with_multydots.65560759.jpg',
'http://images.fitnessmagazine.mdpcdn.com/sites/story/image.png',
'http://images.fitnessmagazine.mdpcdn.com/sites/story/without_ext',   
];
foreach（$examples作为$example）{
preg#u match（'/（？：.+\/）（.+\.（png | jpg | jepg））[？#]？.*$/'，$example，$matches）；
if（isset（$matches[1]）&&$matches[1]）{
echo“Url:{$example}，图像名称：{$matches[1]}\n”；
}否则{
echo“Url:{$example}不是图像Url\n”；
}
}

印刷品：

Url: http://images.fitnessmagazine.mdpcdn.com/sites/story/with_query.jpg?itok=b8HiA95H, image name: with_query.jpg 
Url: http://images.fitnessmagazine.mdpcdn.com/sites/story/with_hash.jpg#hghgh, image name: with_hash.jpg 
Url: http://images.fitnessmagazine.mdpcdn.com/sites/story/with_query.jpg?, image name: with_query.jpg 
Url: http://images.fitnessmagazine.mdpcdn.com/sites/story/with_hash.jpg#, image name: with_hash.jpg 
Url: http://images.fitnessmagazine.mdpcdn.com/sites/story/with_multydots.65560759.jpg, image name: with_multydots.65560759.jpg 
Url: http://images.fitnessmagazine.mdpcdn.com/sites/story/image.png, image name: image.png 
Url: http://images.fitnessmagazine.mdpcdn.com/sites/story/without_ext is not image url 

---

如果要从忽略uri参数的url获取文件名，可以尝试以下操作：

$url = 'http://host/filename.ext?params';
$parsedUrl = parse_url($url);
$pathInfo = pathinfo($parsedUrl['path']);
print_r($pathInfo);
Array
(
    [dirname] => /
    [basename] => filename.ext
    [extension] => ext
    [filename] => filename
)

---

严格来说，这不是图像的名称，尽管大多数浏览器在大部分时间保存图像时都会使用这个名称，因为web上的大多数实体没有名称，但这可能是一个不错的选择。如果prelovac.com的负责人真的想设置一个名称，他们会使用contentdisposition标题。虽然浏览器仍然可以忽略这一点，但如果您想匹配大多数用户将看到的保存为的文件，然后首先检查URI的路径信息，如果没有，只检查URI的路径信息。有一些PHP函数可以一次完成这项工作。尝试添加一些解释来提高您的URI的质量answer@Sinha这正是我一直在寻找的，非常感谢你的回答。@ArakTai'Roth，很高兴知道这对你有帮助。：）对于那些没有从上面获得工作链接的用户，它是

if (strpos($url, '?') !== false) {
    $t = explode('?',$url);
    $url = $t[0];            
}      

$pathinfo = pathinfo($url);
echo $pathinfo['filename'].'.'.$pathinfo['extension'];

Url: http://images.fitnessmagazine.mdpcdn.com/sites/story/with_query.jpg?itok=b8HiA95H, image name: with_query.jpg 
Url: http://images.fitnessmagazine.mdpcdn.com/sites/story/with_hash.jpg#hghgh, image name: with_hash.jpg 
Url: http://images.fitnessmagazine.mdpcdn.com/sites/story/with_query.jpg?, image name: with_query.jpg 
Url: http://images.fitnessmagazine.mdpcdn.com/sites/story/with_hash.jpg#, image name: with_hash.jpg 
Url: http://images.fitnessmagazine.mdpcdn.com/sites/story/with_multydots.65560759.jpg, image name: with_multydots.65560759.jpg 
Url: http://images.fitnessmagazine.mdpcdn.com/sites/story/image.png, image name: image.png 
Url: http://images.fitnessmagazine.mdpcdn.com/sites/story/without_ext is not image url 

$url = 'http://host/filename.ext?params';
$parsedUrl = parse_url($url);
$pathInfo = pathinfo($parsedUrl['path']);
print_r($pathInfo);
Array
(
    [dirname] => /
    [basename] => filename.ext
    [extension] => ext
    [filename] => filename
)