Php 为json输出构建多维数组
希望以以下格式输出json:Php 为json输出构建多维数组,php,json,Php,Json,希望以以下格式输出json: [{"Montgomery":[{"red":"12:34:56","yellow":"11:44:46","orange":"10:54:36","green":"9:24:26","purple":"8:14:16"}],"Suburban":[{"red":"12:34:56","yellow":"11:44:46","orange":"10:54:36","green":"9:24:26","purple":"8:14:16"}],"Shady Grove
[{"Montgomery":[{"red":"12:34:56","yellow":"11:44:46","orange":"10:54:36","green":"9:24:26","purple":"8:14:16"}],"Suburban":[{"red":"12:34:56","yellow":"11:44:46","orange":"10:54:36","green":"9:24:26","purple":"8:14:16"}],"Shady Grove Adventist":[{"red":"12:34:56","yellow":"11:44:46","orange":"10:54:36","green":"9:24:26","purple":"8:14:16"}],"Holy Cross":[{"red":"12:34:56","yellow":"11:44:46","orange":"10:54:36","green":"9:24:26","purple":"8:14:16"}],"Washington Adventist":[{"red":"12:34:56","yellow":"11:44:46","orange":"10:54:36","green":"9:24:26","purple":"8:14:16"}]}]
我的代码:
$xyz[] = array("Montgomery"=> array("Red" => "12:00", "Yellow" => "14:00"));
$xyz[] = array("Suburban"=> array("Yellow" => "16:00"));
echo '[' . json_encode($xyz) . ']';
我的结果:
[[{"Montgomery":{"Red":"12:00","Yellow":"14:00"}},{"Suburban":{"Yellow":"16:00"}}]]
这将为您提供以下结构:
$container = array();
$container['Montgomery'] = array(array('red' => '12:34:56', 'yellow' => '11:44:46'));
$container['Suburban'] = array(array('red' => '12:34:56', 'yellow' => '11:44:46'));
echo json_encode(array($container));
您可以使用对象,类似于这样的东西您需要稍微清理一下:
class Church {
public $red = "";
public $yellow = "";
public $orange = "";
public $green = "";
public $purple = "";
}
class XYZ {
public $Montgomery = new Church();
public $Shad_Grove_Adventist = new Church();
public $Holy_Cross = new Church();
public $Washington_Adventist = new Church();
}
$xyz = new XYZ();
$xyz->Montgomery->red = "12:00";
...
然后输出JSON:
echo '[' . json_encode($xyz) . ']';
它不会与您想要的JSON输出完美匹配,但它会提供更好的可读性和更大的灵活性。您想要的输出有一个数组[]作为其顶级项。JSON中的[]对应于PHP中的数字数组。JSON数组用于包含有序的项集合 顶级数组包含一个项目,即JSON对象{}。PHP对象stdClass或关联数组将转换为JSON格式。JSON对象用于创建键值对集合 要生成所需的输出,请使用PHP构建数据,如下所示:
// Top-level numeric array.
$container = array();
// Only item in top-level array.
$item = array();
// The value of each of these items will be a numeric array.
$item['Montgomery'] = array();
// Create a new associative array, and push that onto the list array.
$subItem = array("red" => "12:34:56",
"yellow" => "11:44:46",
"orange" => "10:54:36",
"green" => "9:24:26",
"purple" => "8:14:16");
$item['Montgomery'][] = $subItem;
$container[] = $item;
// ...Add more items...
print json_encode($container);
或者,如果您想一次全部构建:
$container = array(
array(
"Montgomery" => array(
array("red" => "12:34:56",
"yellow" => "11:44:46",
"orange" => "10:54:36",
"green" => "9:24:26",
"purple" => "8:14:16"
)
)
// ...More items...
)
);
print json_encode($container);
请注意,有些位置在数组中具有数组。这是为了构建关联数组并将其添加为数字数组的唯一成员。这相当于在[]内有一个{}。这是一个带空格的有效变量吗?公众$Shad_Grove基督复临安息日会;抱歉,它需要下划线。太好了,这正是我想要的@wwwslinger:我想把它们都保存在一个数组中,而不是创建一个类,但是非常好的选择,谢谢你们。