PHP:正在寻找引号内str_getcsv换行错误的解决方法

我有这样一个CSV：

Year,Make,Model,Description,Price
1997,Ford,E350,"ac, abs, moon",3000.00
1999,Chevy,"Venture ""Extended Edition""","",4900.00
1999,Chevy,"Venture ""Extended Edition, Very Large""","",5000.00
1996,Jeep,Grand Cherokee,"MUST SELL! ""TODAY""
air, moon roof, loaded",4799.00

如何将其转换为二维数组，而不将最后一行错误地放入自己的数组中？

---

以下是问题的说明（也在此处托管）：

$s2=
str_getcsv（）
希望字符串是一个CSV记录，而不是整个CSV文件

如果内存中有CSV文件，则可以使用
php://memory
将其转换为可使用
fgetcsv（）
读取的流。这将正确解析记录

<?php
$s2=<<<EOD
Year,Make,Model,Description,Price
1997,Ford,E350,"ac, abs, moon",3000.00
1999,Chevy,"Venture ""Extended Edition""","",4900.00
1999,Chevy,"Venture ""Extended Edition, Very Large""","",5000.00
1996,Jeep,Grand Cherokee,"MUST SELL! ""TODAY""
air, moon roof, loaded",4799.00
EOD;
$stream = fopen("php://memory", "r+");
fwrite($stream, $s2);
rewind($stream);
while ($row = fgetcsv($stream)) {
  print_r($row);
}

您需要使用
fgetcsv（）
。如果逐行读取文件，然后使用
str_getcsv（）
，则字符串中不会有下一行。
str_getcsv（）
希望字符串仅为文件的一条记录，而不是整个文件。
<?php
$s2=<<<EOD
Year,Make,Model,Description,Price
1997,Ford,E350,"ac, abs, moon",3000.00
1999,Chevy,"Venture ""Extended Edition""","",4900.00
1999,Chevy,"Venture ""Extended Edition, Very Large""","",5000.00
1996,Jeep,Grand Cherokee,"MUST SELL! ""TODAY""
air, moon roof, loaded",4799.00
EOD;
$stream = fopen("php://memory", "r+");
fwrite($stream, $s2);
rewind($stream);
while ($row = fgetcsv($stream)) {
  print_r($row);
}