我得到了一个“答案”;警告:mysqli_fetch_array()要求参数1为mysqli_result;Php中的错误

我得到了一个“答案”;警告:mysqli_fetch_array()要求参数1为mysqli_result;Php中的错误,php,mysqli,Php,Mysqli,试图为管理员创建显示订单页,但在我的代码中出现此错误。经过这么多的努力,我没有发现这个错误。救救我 错误:警告:mysqli\u fetch\u array()要求参数1为mysqli\u结果 这是我的密码: <div class="grid_10"> <div class="box round first"> <h2>Display Order</h2>

试图为管理员创建显示订单页,但在我的代码中出现此错误。经过这么多的努力,我没有发现这个错误。救救我

错误:警告:mysqli\u fetch\u array()要求参数1为mysqli\u结果

这是我的密码:

      <div class="grid_10">
        <div class="box round first">
            <h2>Display Order</h2>
              <div class="block">
               
                <?php
                $res = mysqli_query($link, "select * from 'confirm_order_address' order by id desc");
                echo "<table border='1'>";
                echo "<tr>";
                echo "<td style='font-weight:bold'>"; echo "fullname"; echo "</td>";
                echo "<td style='font-weight:bold'>"; echo "mobileno"; echo "</td>";
                echo "<td style='font-weight:bold'>"; echo "email"; echo "</td>";
                echo "<td style='font-weight:bold'>"; echo "pincode"; echo "</td>";
                echo "<td style='font-weight:bold'>"; echo "address"; echo "</td>";
                echo "<td style='font-weight:bold'>"; echo "landmark"; echo "</td>";
                echo "<td style='font-weight:bold'>"; echo "city"; echo "</td>";
                echo "</tr>";
                
                while($row = mysqli_fetch_array($res))
                {
                    echo "<tr>";
                    echo "<td>"; echo $row["fullname"]; echo "</td>";
                    echo "<td>"; echo $row["mobileno"]; echo "</td>";
                    echo "<td>"; echo $row["email"]; echo "</td>";
                    echo "<td>"; echo $row["pincode"]; echo "</td>";
                    echo "<td>"; echo $row["address"]; echo "</td>";
                    echo "<td>"; echo $row["landmark"]; echo "</td>";
                    echo "<td>"; echo $row["city"]; echo "</td>";
                    echo "</tr>";
                }
                echo "</table>";
                
                ?>
                
            </div>
        </div>
     </div>

显示顺序

显示顺序

如果(!$res){printf(mysqli_error($link));exit;}
表名不能用单引号括起来,检查错误
if(!$res){printf(mysqli_error($link));exit;}的最佳方法就是对您所更改的内容/问题进行一点解释。使用
select*from confirm\u order\u address order by id desc
<div class="grid_10">
    <div class="box round first">
        <h2>Display Order</h2>
          <div class="block">
           
            <?php
            $sql_select = 'SELECT * FROM confirm_order_address ORDER BY id DESC';
            $result_select = $link->query($sql_select);
            if ($result_select->num_rows > 0) {
            echo "<table border='1'>";
            echo "<tr>";
            echo "<td style='font-weight:bold'>"; echo "fullname"; echo "</td>";
            echo "<td style='font-weight:bold'>"; echo "mobileno"; echo "</td>";
            echo "<td style='font-weight:bold'>"; echo "email"; echo "</td>";
            echo "<td style='font-weight:bold'>"; echo "pincode"; echo "</td>";
            echo "<td style='font-weight:bold'>"; echo "address"; echo "</td>";
            echo "<td style='font-weight:bold'>"; echo "landmark"; echo "</td>";
            echo "<td style='font-weight:bold'>"; echo "city"; echo "</td>";
            echo "</tr>";
            
            while ($row_select = $result_select->fetch_assoc()) {
                echo "<tr>";
                echo "<td>"; echo $row["fullname"]; echo "</td>";
                echo "<td>"; echo $row["mobileno"]; echo "</td>";
                echo "<td>"; echo $row["email"]; echo "</td>";
                echo "<td>"; echo $row["pincode"]; echo "</td>";
                echo "<td>"; echo $row["address"]; echo "</td>";
                echo "<td>"; echo $row["landmark"]; echo "</td>";
                echo "<td>"; echo $row["city"]; echo "</td>";
                echo "</tr>";
            }

            echo "</table>";
            }
            ?>
            
        </div>
    </div>
 </div>