Php 使用cURL将表单数据发布到简单表单
我有一个简单的示例表单Php 使用cURL将表单数据发布到简单表单,php,curl,Php,Curl,我有一个简单的示例表单myForm.php <html> <head> <title>Curling and Enjoying?</title> </head> <body> <form action="print.php" method="post"> <p>First name: <input type="text" name="firstname" /></p>
myForm.php
<html>
<head>
<title>Curling and Enjoying?</title>
</head>
<body>
<form action="print.php" method="post">
<p>First name: <input type="text" name="firstname" /></p>
<p>Last name: <input type="text" name="lastname" /></p>
<input type="submit" name="submit" value="Submit" />
</form>
</body>
</html>
<?php
echo("First name: " . $_POST['firstname'] . "<br />\n");
echo("Last name: " . $_POST['lastname'] . "<br />\n");
?>
如果可能,在向表单发布数据时,如何使用cURL通过向服务器提交参数来获得正确的HTML响应
当我运行命令时:
$curl-d“firstname=Ray&lastname;=Charles”http://mysiteurl.com/myForm.php
<html>
<head>
<title>Curling and Enjoying?</title>
</head>
<body>
<form action="print.php" method="post">
<p>First name: <input type="text" name="firstname" /></p>
<p>Last name: <input type="text" name="lastname" /></p>
<input type="submit" name="submit" value="Submit" />
</form>
</body>
</html>
<?php
echo("First name: " . $_POST['firstname'] . "<br />\n");
echo("Last name: " . $_POST['lastname'] . "<br />\n");
?>
我只从myForm.php中获取HTML,提交目标应该是
print.php
,而不是myForm.php
$ curl -d "firstname=Ray&lastname=Charles" http://mysiteurl.com/print.php
您可能想要curl print.php而不是myForm.php