Php 删除变量中的数组

Php 删除变量中的数组,php,arrays,variables,Php,Arrays,Variables,在我的内容管理系统中,变量$data输出以下内容: Array ( [name] => last_visit [value] => 1211809129 [expire] => 1558705129 [domain] => [path] => / [prefix] => exp_ [httponly] => 1 [secure_cookie] => 0 ) Array ( [name] => last_activity [value] =&

在我的内容管理系统中,变量$data输出以下内容:

Array ( [name] => last_visit [value] => 1211809129 [expire] => 1558705129 [domain] => [path] => / [prefix] => exp_ [httponly] => 1 [secure_cookie] => 0 ) 
Array ( [name] => last_activity [value] => 1527169129 [expire] => 1558705129 [domain] => [path] => / [prefix] => exp_ [httponly] => 1 [secure_cookie] => 0 ) 
Array ( [name] => csrf_token [value] => e39fe1edcd0bc48a6e35985069a [expire] => 1527176329 [domain] => [path] => / [prefix] => exp_ [httponly] => 1 [secure_cookie] => 0 ) 
我需要修改变量,删除一个数组,例如,第二个数组的'name'为'last_activity'

由于数组没有键,我无法选择它来删除它

我想我可以用unset,比如:

unset($data[1]);
但这不起作用


如何从变量中删除数组

您可以这样做:

foreach ($data as $key => $value)
{
    if ($value['name'] === 'last_activity') {
        unset($data[$key]);
    }
}
使用阵列拼接:


看起来你已经在一个循环中转储了var_。您可以将$data替换为var_转储吗?这不会删除数组。它只删除该数组中的那个键,这是一种肮脏的方式,而不是如何与数组交互进行var_转储并注意到您已经破坏了结构。正确的函数是数组_splice@Mike如果OP需要结构保持机智,我对此表示怀疑,那么他可以选择您的答案:
<?php
$data = array();
$data[] = ['name' => 'last_visit', 'value' => '1211809129', 'expire' => '1558705129', 'domain' => '', 'path' => '/', 'prefix' => 'exp_', 'httponly' => 1, 'secure_cookie' => 0];
$data[] = ['name' => 'last_activity', 'value' => '1527169129', 'expire' => '1558705129', 'domain' => '', 'path' => '/', 'prefix' => 'exp_', 'httponly' => 1, 'secure_cookie' => 0 ];
$data[] = ['name' => 'csrf_token', 'value' => 'e39fe1edcd0bc48a6e35985069a', 'expire' => '1527176329', 'domain' => '', 'path' => '/', 'prefix' => 'exp_', 'httponly' => 1, 'secure_cookie' => 0];

var_dump($data);

for($i = 0; $i < sizeof($data); $i++){
    if($data[$i]['name'] == 'last_activity'){
            array_splice($data, $i, $i);
    }
}

var_dump($data);
?>