Php 如何使用mysql查询显示排名

和查询：

user_id | date | point
    1      20      4
    2      20      3
    3      20      2
    1      21      1
    2      21      3
    3      21      5
    1      23      2
    2      23      4
    3      23      5

---

如何在此查询中显示排名？

首先，您需要首先将delcare@row作为变量

类似于

set@row=0；从用户组中选择用户id，总和（点）作为点，@row:=@row+1作为排名，按用户id按总和（点）描述排序
试试这个

SELECT user_id, SUM(point) AS point, @row:=@row+1 rank FROM users GROUP BY user_id

您可以使用以下方法处理声明零件：

SET @row=0;
SELECT user_id, SUM(point) AS point, @row:=@row+1 rank FROM users GROUP BY user_id

我想你应该这样写：

SELECT user_id, SUM(point) AS point, @row:=@row+1 rank FROM users, (SELECT @row := 0) r GROUP BY user_id

试试这个

SELECT user_id, SUM(point) AS point, @row:=@row+1 AS rank FROM users GROUP BY user_id JOIN (SELECT @row := 0) r;

应具有AS to别名@row to rank和order by on point，以使其按正确的顺序排列：-

SELECT user_id,points, @row:=@row+1 AS Row 
from (
  SELECT user_id, 
    SUM(point) AS points  rank 
  FROM users 
  GROUP BY user_id 
  Sort by points);

select
user\u id
not
userid
SELECT user_id, SUM(point) AS point, @row:=@row+1 AS rank 
FROM users 
CROSS JOIN (SELECT @row:=0) Sub1
GROUP BY user_id
ORDER BY point DESC