Php 如何在laravel中用雄辩的ORM编写内部连接？

我有一个名为

建筑物

和

公寓

建筑物表

Building_Id | Building_Name | .......| Building_Owned_By | ....

Flat_Id | Flat_Name | ........| Fk_Building_Id | .....

扁平表

Building_Id | Building_Name | .......| Building_Owned_By | ....

Flat_Id | Flat_Name | ........| Fk_Building_Id | .....

在我的模型中

建筑

class Building extends Eloquent {
    protected $primaryKey = "Building_Id";
    protected $table = 'buildings';
    .......
    .......
    public function flat()
    {
        return  $this->hasMany('Flat', 'Fk_Building_Id', 'Building_Id');
    }
}

平坦

class Flat extends Eloquent {
    protected $primaryKey = "Flat_Id";
    protected $table = 'flats';
    .......
    .......
    public function building() {
        return $this->belongsTo('Building','Fk_Building_Id', 'Building_Id');
    }
}

在我的控制器里

$flats =  Flat::where('Fk_Building_Id', '=',$buildingid)
               ->where('Building_Owned_By', '=',Auth::user()->Login_Id)
               ->orderBy('Flat_Name')
               ->get(array('Flat_Id as flatId', 'Flat_Name as flatName'))
               ->toArray();

但它什么也不返回

如何在雄辩的Orm中执行内部联接（我不想使用fluent查询）

更新

Building_Id | Building_Name | .......| Building_Owned_By | ....

Flat_Id | Flat_Name | ........| Fk_Building_Id | .....

感谢@Creator的宝贵时间和帮助。他帮了我很多忙找到了这个。解决方案是我们必须使用，并将代码重写为

$flats =  Flat::whereHas('building', function($q){ 
                      $q->where('Building_Owned_By', '=',Auth::user()->Login_Id);
               })
               ->where('Fk_Building_Id', '=',$buildingid)
               ->orderBy('Flat_Name')
               ->get(array('Flat_Id as flatId', 'Flat_Name as flatName'))
               ->toArray();

这样做：

class Building extends Eloquent {
protected $primaryKey = "Building_Id";
protected $table = 'buildings';
.......
.......
public function flat()
{
    return  $this->HasMany('Flat', 'Fk_Building_Id', 'Building_Id');
}

}

查询以获取包含所有公寓的建筑：

   Building::with('flat')->(some_condition)->get();




class Flat extends Eloquent {
   protected $primaryKey = "Flat_Id";
    protected $table = 'flats';
   .......
   .......
  public function building() {
     return $this->HasOne('Building','Fk_Building_Id', 'Building_Id');
   }
}

查询以获取包含建筑信息的平面

      Flat::with('building')
          ->where('Building_Owned_By', '=',Auth::user()->Login_Id)         
          ->orderBy('Flat_Name')
          ->get(array('Flat_Id as flatId', 'Flat_Name as flatName'))
          ->toArray();

试试这个：

Flat::with(array('building'=>function($query){
    $query->where('Building_Owned_By', '=',Auth::user()->Login_Id) 
 }))->where('Fk_Building_Id', '=',$buildingid)->orderBy('Flat_Name')
    ->get(array('Flat_Id as flatId', 'Flat_Name as flatName'))->toArray();

---

每个公寓都有一个buildingId，也可能有两个公寓有相同的buildingId。我的意思是每个建筑不包含任何平面。这意味着一套公寓只能有一栋楼。所以有人应该工作。你试过上面的代码吗？是的…我也试过上面的代码。它返回空值？如何查看任何sql错误或类似的内容您需要从php.ini打开错误报告。再检查一下答案。@manuthalasseril，没问题，伙计！享受拉威尔！！做事要循序渐进，避免出错。这是代码的关键。干杯