Php 如何从记录集中获取数组中的2个值

使用静态数据很简单

 $items = array( "Great Bittern"=>"Botaurus stellaris",
 "Heuglin's Gull"=>"Larus heuglini" );

现在我想用数据库中的动态数据来实现这一点

 $items = array();

 do{
     $items[] = $row_Recordset1['ID'] => $row_Recordset1['ARTIST'];

 } while ($row_Recordset1 = mysql_fetch_assoc($Recordset1));

它只使用了一个$row_记录集，但是当我放置=>和第二个记录集时，它给了我一个错误

分析错误：语法错误，意外的T\u双箭头

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提前感谢

应该如下所示：

$items = array();
while ($row = mysql_fetch_assoc($resource)) {
  $items[$row['ID']] = $row['ARTIST'];
}

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它应该如下所示：

$items = array();
while ($row = mysql_fetch_assoc($resource)) {
  $items[$row['ID']] = $row['ARTIST'];
}

选择1

$items[$row_Recordset1['ID']] = $row_Recordset1['ARTIST'];

或许

 $items[] =array($row_Recordset1['ID'] => $row_Recordset1['ARTIST']);

选择1

$items[$row_Recordset1['ID']] = $row_Recordset1['ARTIST'];

或许

 $items[] =array($row_Recordset1['ID'] => $row_Recordset1['ARTIST']);