Python错误："；“字符串索引超出范围”；

我用python制作了一个Pig拉丁翻译程序（包含所有特定规则），下面是我的代码：

print ("Enter some text here to be translated to Pig Latin: ");
text = input("> ");

wordlist = [];
letterlist = [];

for word in text:
    if word[0] != "a" and word[0] != "e" and word[0] != "i" and word[0] != "o" and word[0] != "u":
        if word[1] == "a" or word[1] == "e" or word[1] == "i" or word[1] == "o" or word[1] == "u":
            for number in range(1, len(word) - 1):
                letterlist.append(word[number]);
            letterlist.append(word[0]);
            letterlist.append("ay");
            new_word = "".join(letterlist);
            wordlist.append(new_word);
            letterlist = [];
        else:
            for number in range(2, len(word) - 2):
                letterlist.append(word[number]);
            letterlist.append(word[0]);
            letterlist.append(word[1]);
            letterlist.append("ay");
            new_word = "".join(letterlist);
            wordlist.append(new_word);
            letterlist = [];
    else:
        letterlist.append(word);
        letterlist.append("way");
        new_word = "".join(letterlist);
        wordlist.append(new_word);
        letterlist = [];

pigLatin = " ".join(wordlist);
print (pigLatin);

我得到一个指向该行的错误：

if word[1] == "a" or word[1] == "e" or word[1] == "i" or word[1] == "o" or word[1] == "u":

---

表示字符串索引超出范围。请帮忙

这里有几个问题。我将通过在代码中添加#注释来构建我的答案

一般来说，您应该首先将字符串中的输入拆分为“单词”列表（不包括空格的字符组）。此外，在检查单词[1]的值之前，应该添加一个块，如

if len（word）<2:；继续

，以便正确处理只有一个字符长的提交（例如字母“a”）

---

如果输入一个单字母单词，单词[1]将是什么？如何将两个恭维条件嵌套在一起？@jwodder忘记单字母输入，文本中单词的

行：

从字符串

文本中提取一个字符。这对于多字母输入也是一个错误
print ("Enter some text here to be translated to Pig Latin: ");
text = input("> ");

wordlist = [];
letterlist = [];

for word in text: # how do you know that text will be separated into words?
# as of right now, text is a string of characters, not a list of words. you 
# should use something like words = text.split(), and then iterate over words. 
# .split() converts a string into a list of strings. by default it separates
# according to the whitespace between characters.
    if word[0] != "a" and word[0] != "e" and word[0] != "i" and word[0] != "o" and word[0] != "u":
        if word[1] == "a" or word[1] == "e" or word[1] == "i" or word[1] == "o" or word[1] == "u": 
# here's the problem referenced in your question. 
# since text is a string of characters, when you iterate over it with `for`,
# you will be looking at one character at a time. each character has only one 
# index, 0. for example 'e'[0] will return 'e', but 'e'[1] will throw an error,
# since there is no index 1.  

            for number in range(1, len(word) - 1):
                letterlist.append(word[number]);
            letterlist.append(word[0]);
            letterlist.append("ay");
            new_word = "".join(letterlist);
            wordlist.append(new_word);
            letterlist = [];
        else:
            for number in range(2, len(word) - 2):
                letterlist.append(word[number]);
            letterlist.append(word[0]);
            letterlist.append(word[1]);
            letterlist.append("ay");
            new_word = "".join(letterlist);
            wordlist.append(new_word);
            letterlist = [];
    else:
        letterlist.append(word);
        letterlist.append("way");
        new_word = "".join(letterlist);
        wordlist.append(new_word);
        letterlist = [];

pigLatin = " ".join(wordlist);
print (pigLatin);