Python 如何在Django Rest框架中为基于函数的视图添加过滤

我正在尝试向基于函数的视图添加过滤器。使用基于类的视图，我能够向视图添加过滤器。但我很好奇是否可以将过滤添加到这个基于函数的视图中。我需要通过网络搜索按名称筛选主题。我怎样才能做到这一点

@api_view(['GET'])
@permission_classes([IsAuthenticated])
def TeacherSubject(request):
    teacher = TeacherProfile.objects.get(user=request.user)
    subject = Subject.objects.filter(author=teacher).order_by('-id')
    paginator = PageNumberPagination()
    paginator.page_size = 5
    result_page = paginator.paginate_queryset(subject, request)
    serializer = SubjectSerializer(result_page,many=True)
    return paginator.get_paginated_response(serializer.data)

你可以用。比如说

# filters.py

class ProductFilter(django_filters.FilterSet):
    class Meta:
        model = Product
        fields = ['price', 'release_date']

# views.py
...
from .filters import ProductFilter


@api_view(['GET'])
@permission_classes([IsAuthenticated])
def product_list(request):
    queryset = Product.objects.all()
    filterset = ProductFilter(request.GET, queryset=queryset)
    if filterset.is_valid():
         queryset = filterset.qs
    serializer = ProductSerializer(queryset, many=True)
    return Response(serializer.data)

如果需要引发验证错误，请使用此

from .filters import ProductFilter
from django_filters.utils import translate_validation

@api_view(['GET'])
@permission_classes([IsAuthenticated])
def product_list(request):
    filterset = ProductFilter(request.GET, queryset=Product.objects.all())
    if not filterset.is_valid():
         raise translate_validation(filterset.errors)
    serializer = ProductSerializer(filterset.qs, many=True)
    return Response(serializer.data)

分页

from .filters import ProductFilter
from django_filters.utils import translate_validation
from rest_framework.pagination import PageNumberPagination

@api_view(['GET'])
@permission_classes([IsAuthenticated])
def product_list(request):
    paginator = PageNumberPagination()
    paginator.page_size = 5
    
    filterset = ProductFilter(request.GET, queryset=Product.objects.all())
    if not filterset.is_valid():
         raise translate_validation(filterset.errors)

    queryset = paginator.paginate_queryset(filterset.qs, request)
    serializer = ProductSerializer(queryset, many=True)
    return paginator.get_paginated_response(serializer.data)

---

@api_view（['GET']）def SubjectList（request）：subjects=SubjectFilter（request.GET，queryset=Subject.objects.all（））serializer=subjectviewsserializer（subjects，many=True）在触发api后返回响应（serializer.data）

它给出的“SubjectFilter”对象不是iterableyep，您是对的。我正在更新答案。现在检查。是的，它正在工作，但没有分页。使用分页时，它会给出响应中的所有结果。不知何故，您没有正确设置分页。最新答案