Python 如何正确访问google语音到文本api？

我正在尝试使用谷歌语音文本api，我已经设置了我的密钥，但我不知道如何访问api，我不断收到错误

import pyaudio
import speech_recognition as sr
r = sr.Recognizer()
GOOGLE_KEY = ""
with sr.Microphone() as source:
print('Speak now')
audio = r.listen(source)
print("Time is over")

try:
    print("TEXT:" + r.recognize_google(audio,key= GOOGLE_KEY))
except sr.RequestError as e:
    print("Could not request results from Google Speech Recognition service; {0}".format(e))
    raise
except sr.UnknownValueError:
    print("Google Speech Recognition could not understand audio")

这些都是我得到的错误 ，回溯（最近一次呼叫最后一次）：

文件“/Users/bob/PycharmProject/grid/venv/lib/python3.7/site packages/speech\u recognition/\uuuuuu init\uuuuuu.py”，第840行，在谷歌的recognition\u中
响应=urlopen（请求，超时=self.operation\u超时）
urlopen中的文件“/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/urllib/request.py”，第222行
返回opener.open（url、数据、超时）
打开文件“/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/urllib/request.py”，第531行
响应=方法（请求，响应）
http_响应中的文件“/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/urllib/request.py”，第641行
“http”、请求、响应、代码、消息、hdrs）
文件“/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/urllib/request.py”，第569行出错
返回自我。调用链（*args）
文件“/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/urllib/request.py”，第503行，在调用链中
结果=func（*args）
文件“/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/urllib/request.py”，第649行，默认为http\u error\u
raise HTTPError（请求完整的url、代码、消息、hdrs、fp）
urllib.error.HTTPError:HTTP错误403:禁止
在处理上述异常期间，发生了另一个异常：
回溯（最近一次呼叫最后一次）：
文件“/Users/bob/PycharmProject/grid/audio.py”，第11行，在
打印（“文本：+r.recognize_谷歌（音频，键=谷歌键））
文件“/Users/bob/PycharmProject/grid/venv/lib/python3.7/site packages/speech_recognition/_init__.py”，第842行，在谷歌的recognition_中
raise RequestError（“识别请求失败：{}”。格式（e.reason））
语音识别。请求错误：识别请求失败：禁止

   File "/Users/bob/PycharmProject/grid/venv/lib/python3.7/site-packages/speech_recognition/__init__.py", line 840, in recognize_google
response = urlopen(request, timeout=self.operation_timeout)
  File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/urllib/request.py", line 222, in urlopen
return opener.open(url, data, timeout)
  File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/urllib/request.py", line 531, in open
response = meth(req, response)
  File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/urllib/request.py", line 641, in http_response
'http', request, response, code, msg, hdrs)
  File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/urllib/request.py", line 569, in error
return self._call_chain(*args)
  File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/urllib/request.py", line 503, in _call_chain
result = func(*args)
  File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/urllib/request.py", line 649, in http_error_default
raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 403: Forbidden

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File "/Users/bob/PycharmProject/grid/audio.py", line 11, in <module>
print("TEXT:" + r.recognize_google(audio,key= GOOGLE_KEY))
      File "/Users/bob/PycharmProject/grid/venv/lib/python3.7/site-packages/speech_recognition/__init__.py", line 842, in recognize_google
raise RequestError("recognition request failed: {}".format(e.reason))
speech_recognition.RequestError: recognition request failed: Forbidden