随机数网格4 x 6 Python 3_Python_Python 3.x_Random_Numbers

随机数网格4 x 6 Python 3

python python-3.x random

随机数网格4 x 6 Python 3,python,python-3.x,random,numbers,Python,Python 3.x,Random,Numbers,我对Python 3非常陌生，希望生成一个随机网格4x6数字。我尝试过各种方法，但最终都是在新行上打印，或者在每行上打印4x6相同的数字等等一些代码示例（我尝试了许多不同的方法，但我必须重新键入它们，因为我正在使用linux上的virtualbox来运行Python： import random def grid_maker(h,v): for y in range(1, 5): x = random.randint(1, 100) grid = [[str(x) for _ i

我对Python 3非常陌生，希望生成一个随机网格4x6数字。我尝试过各种方法，但最终都是在新行上打印，或者在每行上打印4x6相同的数字等等

一些代码示例（我尝试了许多不同的方法，但我必须重新键入它们，因为我正在使用linux上的virtualbox来运行Python：

import random

def grid_maker(h,v):
 for y in range(1, 5):
  x = random.randint(1, 100)
  grid = [[str(x) for _ in range(v)] for _ in range (h)]
  grid[0][0] = "o"
  return grid
print ('\n'.join(''.join(row) for row in grid_maker(6,5)))

输出

期望输出

82 2 30 9 
45 65 54 14
23 4 32 42 
8 84 40 80
43 23 5 62 
23 43 3 5

[[34], [12], [2], [15]]
[[64], [34], [53], [4]]
[[35], [34], [61], [33]]
[[34], [55], [64], [23]]

另一个例子

for t in range(1, 5)
 i = random.randint(1, 100)
 grid = [[i], [i], [i], [i]]
 from pprint import pprint
 pprint(grid)

ar = []
    for t in range(1, 5):
     i = random.randint(1, 100)
     ar.append(i)
    for t in range(1, 7):
     for i in range(1, 5):
      print(ar[t-1], end='')

输出

[[100], [100], [100], [100]]
[[1], [1], [1], [1]]
[[80], [80], [80], [80]]
[[12], [12], [12], [12]]

期望输出

82 2 30 9 
45 65 54 14
23 4 32 42 
8 84 40 80
43 23 5 62 
23 43 3 5

[[34], [12], [2], [15]]
[[64], [34], [53], [4]]
[[35], [34], [61], [33]]
[[34], [55], [64], [23]]

另一个例子

for t in range(1, 5)
 i = random.randint(1, 100)
 grid = [[i], [i], [i], [i]]
 from pprint import pprint
 pprint(grid)

ar = []
    for t in range(1, 5):
     i = random.randint(1, 100)
     ar.append(i)
    for t in range(1, 7):
     for i in range(1, 5):
      print(ar[t-1], end='')

但这会打印出

585858585555555559595959343434342222222288888888root@root：/home/user#

谢谢

您在循环中每次只调用random一次，因此请继续使用相同的值，在列表comp中调用它：

def grid_maker(h,v):
   for y in range(1, 5):
      # add call to list comp to get a new number each iteration
      grid = [[str(random.randint(1,100)) for _ in range(v)] for _ in range (h)]
   grid[0][0] = "o"
   return grid
print ('\n'.join(' '.join(row) for row in grid_maker(6,4))

o 23 47 30 
25 21 32 28
26 76 71 14
54 15 94 77
50 50 29 62
59 92 60 57

如果您不想要

“o”

，那么不要添加它，只需删除

网格[0][0]=“o”

第一个循环也是多余的，因为您不断创建新列表，但只返回一个：

def grid_maker(h, v):
    return [[str(random.randint(1, 100)) for _ in range(v)] for _ in range(h)]

我们也可以在功能中完成这一切：

def grid_maker(h, v):
    return '\n'.join(' '.join(row) for row in  [[str(random.randint(1, 100)) for _ in range(v)] for _ in range(h)])

print(grid_maker(6, 4)) # 6,4 not 6,5

26 96 50 46
4 57 50 80
36 24 23 66
71 33 44 15
54 15 77 54
52 99 60 99

要打印相同逻辑适用的列表列表，每次需要调用randint：

for t in range(6):
    print([[random.randint(1,100)], [random.randint(1,100)], [random.randint(1,100)], [random.randint(1,100)]])

[[90], [57], [21], [11]]
[[84], [80], [100], [47]]
[[25], [37], [87], [97]]
[[78], [90], [100], [74]]
[[96], [83], [59], [2]]
[[83], [19], [90], [4]]

在循环中每次只调用random一次，因此请继续使用相同的值，在列表comp中调用它：

def grid_maker(h,v):
   for y in range(1, 5):
      # add call to list comp to get a new number each iteration
      grid = [[str(random.randint(1,100)) for _ in range(v)] for _ in range (h)]
   grid[0][0] = "o"
   return grid
print ('\n'.join(' '.join(row) for row in grid_maker(6,4))

o 23 47 30 
25 21 32 28
26 76 71 14
54 15 94 77
50 50 29 62
59 92 60 57