如何使用Python套接字发送SIP消息
我需要使用pythonsockets发送SIP消息,我已经让客户端向服务器发送了一些东西,但我无法让客户端向服务器发送SIP消息INVITE如何使用Python套接字发送SIP消息,python,sip,invite,Python,Sip,Invite,我需要使用pythonsockets发送SIP消息,我已经让客户端向服务器发送了一些东西,但我无法让客户端向服务器发送SIP消息INVITE #!/usr/bin/python import socket R_IP = '192.168.2.1' R_PORT = 5060 message = 'INVITE sip:user1110000000350@.com SIP/2.0 To: <sip:user4110000000350@whatever.com>\x0d\x0aF
#!/usr/bin/python
import socket
R_IP = '192.168.2.1'
R_PORT = 5060
message = 'INVITE sip:user1110000000350@.com SIP/2.0 To: <sip:user4110000000350@whatever.com>\x0d\x0aFrom: sip:user9990000000000@rider.com;tag=R400_BAD_REQUEST;taag=4488.1908442942.0\x0d\x0aP-Served-User: sip:user4110000000350@whatever.com\x0d\x0aCall-ID: 00000000-00001188-71C0873E-0@10.44.40.47\x0d\x0aCSeq: 1 INVITE\x0d\x0aContact: sip:user9990000000000@rider.com\x0d\x0aMax-Forwards: 70\x0d\x0aVia: SIP/2.0/TCP 10.44.40.47;branch=z9hG4bK1908442942.4488.0\x0d\x0aContent-Length: 10\x0d\x0a\x0d\x0aRandomText'
def sendPacket():
proto = socket.getprotobyname('tcp')
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)#, proto)
try:
s.connect((R_IP , R_PORT))
s.sendall(message)
except socket.error:
pass
finally:
s.close()
sendPacket()
#/usr/bin/python
导入套接字
R_IP='192.168.2.1'
R_端口=5060
消息='邀请sip:user1110000000350@.comSIP/2.0至:\x0d\x0aFrom:SIP:user9990000000000@rider.com;tag=R400\u坏请求;taag=4488.1908442942.0\x0d\x0aP服务用户:sip:user4110000000350@whatever.com\x0d\x0aCall ID:00000000-00001188-71C0873E-0@10.44.40.47\x0d\x0aCSeq:1邀请\x0d\x0a联系人:sip:user9990000000000@rider.com\x0d\x0aMax转发:70\x0d\x0aVia:SIP/2.0/TCP 10.44.40.47;branch=z9hG4bK1908442942.4488.0\x0d\x0a内容长度:10\x0d\x0a\x0d\x0aRandomText'
def sendPacket():
proto=socket.getprotobyname('tcp')
s=socket.socket(socket.AF_INET,socket.SOCK_STREAM)#,proto)
尝试:
s、 连接((R_IP,R_端口))
s、 发送全部(消息)
除socket.error外:
通过
最后:
s、 关闭()
sendPacket()
你有什么想法吗?好的,我知道,也许它会帮助别人 SIP消息的正确格式如下:
INVITE sip:user11@whatever SIP/2.0
To: <to>
Call-ID: <call_id>
<empty line>
body
INVITE sip:user11@whateverSIP/2.0
致:
呼叫ID:
身体
所以
message='邀请sip:user1110000000350@whatever.comSIP/2.0\r\n收件人:\r\n罗马:SIP:user9990000000000@rider.com;tag=R400\u坏请求;taag=4488.1908442942.0\r\nP服务用户:sip:user4110000000350@whatever.com\r\n调用ID:00000000-00001188-71C0873E-0@10.44.40.47\r\n序号:1邀请\r\n联系人:sip:user9990000000000@rider.com\r\n最大转发:70\r\nVia:SIP/2.0/TCP 10.44.40.47;branch=z9hG4bK1908442942.4488.0\r\n内容长度:10\r\n\r\n随机文本'
\r\n
非常重要,没有空格根据:
到
,从
,CSeq
,呼叫ID
,最大转发
和通过头的
这意味着您在
标题之前正确地添加了换行符,但您的答案也错误地包含来自标题,而不是来自。另外,标题P-Served-User
通常是不必要的。谢谢@Andriy,Froma
可能是一个错误,一个打字错误。然后我不得不用P-Served-User
发送一条消息,我可能没有从代码中删除它。
message = 'INVITE sip:user1110000000350@whatever.com SIP/2.0\r\nTo: <sip:user4110000000350@whatever.com>\r\nFroma: sip:user9990000000000@rider.com;tag=R400_BAD_REQUEST;taag=4488.1908442942.0\r\nP-Served-User: sip:user4110000000350@whatever.com\r\nCall-ID: 00000000-00001188-71C0873E-0@10.44.40.47\r\nCSeq: 1 INVITE\r\nContact: sip:user9990000000000@rider.com\r\nMax-Forwards: 70\r\nVia: SIP/2.0/TCP 10.44.40.47;branch=z9hG4bK1908442942.4488.0\r\nContent-Length: 10\r\n\r\nRandomText'