替换Python中重复的连续字符

我需要创建一个函数，用单个字符替换重复的连续字符，例如：

 'hiiii how are you??' -> 'hi how are you?'
 'aahhhhhhhhhh whyyyyyy' -> 'ah why'
 'foo' -> 'fo'
 'oook. thesse aree enoughh examplles.' -> 'ok. these are enough examples'

---

使用简单的迭代

演示：

def cleanText(val):
    result = []
    for i in val:
        if not result:
            result.append(i)
        else:
            if result[-1] != i:
                result.append(i)
    return "".join(result)

s = ['hiiii how are you??', 'aahhhhhhhhhh whyyyyyy', 'foo', 'oook. thesse aree enoughh examplles.']
for i in s:
    print(cleanText(i))

hi how are you?
ah why
fo
ok. these are enough examples.

输出：

def cleanText(val):
    result = []
    for i in val:
        if not result:
            result.append(i)
        else:
            if result[-1] != i:
                result.append(i)
    return "".join(result)

s = ['hiiii how are you??', 'aahhhhhhhhhh whyyyyyy', 'foo', 'oook. thesse aree enoughh examplles.']
for i in s:
    print(cleanText(i))

hi how are you?
ah why
fo
ok. these are enough examples.

---

您可以尝试使用类似于

（）\1+

的正则表达式，即“something，then more of the same something”，并将其替换为

\1

，即“that first something”

使用

functools.partial

（或您喜欢的任何其他方式）使其成为函数

---

您好

解决方案可以通过以下方式非常简洁地表达：

itertools.groupby

根据给定的键函数对iterable中的对象进行分组。只要密钥相等，组就会累积。如果未给出键函数，则使用项目的标识，在本例中为字符

一旦按对象的标识对它们进行分组，就可以将对象合并到单个字符串中。分组对象作为元组返回，元组包含对象和内部

itertools.\u grouper

对象，出于您的目的，您可以忽略并提取字符

这可以转化为如下功能：

def remove_repeated_characters(s):
    groups = itertools.groupby(s)
    cleaned = ''.join(g[0] for g in groups)
    return cleaned

这将产生预期值：

>>> [remove_repeated_characters(s) 
     for s in ['hiiii how are you??','aahhhhhhhhhh whyyyyyy',
               'foo', 'oook. thesse aree enoughh examplles.']]
['hi how are you?', 'ah why', 'fo', 'ok. these are enough examples.']

---

嗨，圣地亚哥M。！到目前为止你试过什么？如果可能的话，请提供一些代码。如果这个问题是关于家庭作业的，请阅读这篇文章。

def remove_repeated_characters(s):
    groups = itertools.groupby(s)
    cleaned = ''.join(g[0] for g in groups)
    return cleaned

>>> [remove_repeated_characters(s) 
     for s in ['hiiii how are you??','aahhhhhhhhhh whyyyyyy',
               'foo', 'oook. thesse aree enoughh examplles.']]
['hi how are you?', 'ah why', 'fo', 'ok. these are enough examples.']

from collections import OrderedDict

def removeDupWord(word):
   return "".join(OrderedDict.fromkeys(word))

def removeDupSentence(sentence):
    words = sentence.split()
    result = ''
    return ''.join([result + removeDupWord(word) + ' ' for word in words])


sentence = 'hiiii how are you??'
print (removeDupSentence(sentence))

>>> hi how are you?