Python 如何通过预取显示多个相关对象？

更新 我能够在projectmodels.py中实现这一点，但我觉得这属于我的观点。我该怎么做呢？代码：

@property
def related_project_set(self):
    category_id_list = self.category.values_list("id", flat=True)
    return Project.live.filter(category__id__in=category_id_list).exclude(id=self.id)[:5]

---

我想在项目的基于类的通用详细视图中显示按“类别”相关的“项目”。我还使用了Django括号预取相关的Mixin。但是我不明白为什么Python解释器显示的结果与我的模板不同

例如，给定db中的两个项目，我得到以下结果：

>>> from projects.models import Project
>>> Project.objects.all().prefetch_related('category')
[<Project: Avalon Road>, <Project: Piedmont Avenue>]

观点：

from __future__ import absolute_import
from braces.views import PrefetchRelatedMixin

from django.shortcuts import render
from django.views.generic import DetailView, ListView

from .models import Project
from categories.models import Category
from testimonials.models import Testimonial

class ProjectDetailView(PrefetchRelatedMixin, DetailView):
    prefetch_related = ['category']
    queryset = Project.live.all()

    def get_context_data(self, **kwargs):
        """
        Allow the project detail view to display a list of testimonials.

        """
        context = super(ProjectDetailView, self).get_context_data(**kwargs)
        context['testimonial_list'] = Testimonial.displayed.all()
        return context

class ProjectListView(ListView):
    queryset = Project.live.all()

    def get_context_data(self, **kwargs):
        """
        Allow the project list view to display a list of categories.

        """
        context = super(ProjectListView, self).get_context_data(**kwargs)
        context['category_list'] = Category.objects.all()
        return context

模板片段：

<ul>
{% for project in object.category.all %}
    <li>{{ project.title }}</li>
{% endfor %}
</ul>

{object.category.all%中项目的%s}
{{project.title}
{%endfor%}

您提到模板输出与shell不同，但没有显示模板结果。抱歉。以下是模板输出：

厨房

。基本上，这是项目的类别，但不是通过该类别关联的项目。

<ul>
{% for project in object.category.all %}
    <li>{{ project.title }}</li>
{% endfor %}
</ul>