Python 如何检查字符串中的单词是否是列表中的元素？

如何查看“this”或“is”或“a”或“test”是否在测试列表中？

用于拆分字符串，并使用查看字符串中的任何单词是否在您的列表中：

test_string = ("this is a test")

test_list = [dog, cat, test, is, water]

你可以用任何一种

inlist=test_string.split中的元素的test_列表中的任意元素

inlist将为True或False，具体取决于它是否在列表中

例如：

 test_string = ("this is a test")

test_list = ["dog", "cat", "test", "is","water"]
print(any(x in test_list for x in test_string.split()))



In [9]: test_string = ("this is a test")

In [10]: test_string.split()
Out[10]: ['this', 'is', 'a', 'test'] # becomes a list of individual words

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你要问的是集合交点是否为非空

>>test_string = ("this is a test")
>>test_list = ['dog', 'cat', 'water']
>>inlist = any(ele in test_string for ele in test_list)
>>print inlist
False

>>test_string = ("this is a test")
>>test_list = ['dog', 'cat', 'is', 'test' 'water']
>>inlist = any(ele in test_string for ele in test_list)
>>print inlist
True

---

一种选择是正则表达式，例如

>>> set(test_string.split(' ')).intersection(set(test_list))
set(['test', 'is'])

---

可能重复的不应该测试列表=[狗，猫，测试，是，水]而是测试列表=[狗，猫，测试，是，水]？是的，我很匆忙，我经常犯这个错误。谢谢你的提醒eduardnope，你在迭代每个字符，而不是每个单词。我在迭代列表中的每个项目，并检查它是否在字符串中。try s=这是sI解释的OP问题中的测试打印，因为他们只是想看看列表中是否有任何元素出现，他们没有澄清。如果OP想要检查一个完整的单词是否匹配，你是对的。我认为很明显他们想要匹配一个完整的单词

import re

# Test string
test_string = 'this is a test'

# Words to be matched
test_list = ['dog', 'cat', 'test', 'is', 'water']

# Container for matching words
yes = []

# Loop through the list of words
for words in test_list:
    match = re.search(words, test_string)
    if match:
        yes.append(words)

# Output results
print str(yes) + ' were matched'

#['test', 'is'] were matched