如何从线程队列python内部停止线程

当线程与当前正在运行/正在执行的线程内的条件匹配时，我需要停止执行该线程：

下面是我的意思：

• 我们有从1到5的5个数字的列表
• 我们将它们排队，并在Run_Calc函数中处理它们以及10个线程
• 在

  Run\u Calc

  中，如果线程符合

  3

• 输出：

• 我如何做到这一点

---

在某些情况下，线程可能会在“谁会跑得更快”这一术语上竞争，即使它们是按顺序实例化的。
对于您的简单案例，请使用对象在特定事件上同步线程：

import queue
from threading import Thread, Event

q = queue.Queue()
numbers = [1, 2, 3, 4, 5]

for each_num in numbers:
    q.put(each_num)


def run_calc(num, e):
    print("NO IS : {}".format(num))
    if num == 3:
        e.set()
        print("YES I WANT TO EXIT HERE and DONT WANT TO EXECUTE 4,5")


def process_thread(e):
    while not q.empty():
        if e.is_set():
            break
        num = q.get()
        run_calc(num, e)


th_list = []

e = Event()
for i in range(10):
    t = Thread(target=process_thread, args=(e,))
    th_list.append(t)
    t.start()

for th in th_list:
    th.join()

样本输出：

NO IS : 1
NO IS : 2
NO IS : 3
YES I WANT TO EXIT HERE and DONT WANT TO EXECUTE 4,5

可能重复的

import queue
from threading import Thread, Event

q = queue.Queue()
numbers = [1, 2, 3, 4, 5]

for each_num in numbers:
    q.put(each_num)


def run_calc(num, e):
    print("NO IS : {}".format(num))
    if num == 3:
        e.set()
        print("YES I WANT TO EXIT HERE and DONT WANT TO EXECUTE 4,5")


def process_thread(e):
    while not q.empty():
        if e.is_set():
            break
        num = q.get()
        run_calc(num, e)


th_list = []

e = Event()
for i in range(10):
    t = Thread(target=process_thread, args=(e,))
    th_list.append(t)
    t.start()

for th in th_list:
    th.join()

NO IS : 1
NO IS : 2
NO IS : 3
YES I WANT TO EXIT HERE and DONT WANT TO EXECUTE 4,5